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Rina8888 [55]
3 years ago
7

A bicyclist rides 16 miles in 144 minutes. If she continues at this speed, how long will it take her to travel 36 miles?

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0
16/144 = 36/x....16 miles to 144 minutes = 36 miles to x minutes
cross multiply
(16)(x) = (144)(36)
16x = 5184
x = 5184/16
x = 324 minutes 
mario62 [17]3 years ago
6 0
16 -> 144
36 ->  ?

(36x144) / 16 =324 min
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Arithmetic sequences et sn} be an arithmetic sequence that starts with an initial index of 0. The initial term is 3 and the comm
navik [9.2K]

Answer:

(a) The value of s_z is (z+1)(3-z).

(b) The next term in the sequence is -2.

Step-by-step explanation:

(a)

It is given that arithmetic sequence that starts with an initial index of 0.

The initial term is 3 and the common difference is -2.

a_0=3

d=-2

We need to find the value of s_z.

s_z=\sum_{n=0}^{n=z}(a+nd)

where, a is initial term and d is common difference.

s_z=\sum_{n=0}^{n=z}(3-2n)

The sum of an arithmetic sequence with  initial index 0 is

s_n=\frac{n+1}{2}[2a+nd]

where, a is initial term and d is common difference.

Substitute n=z, a=3 and d=-2 in the above formula.

s_z=\frac{z+1}{2}[2(3)+z(-2)]

s_z=\frac{z+1}{2}[2(3-z)]

s_z=(z+1)(3-z)

Therefore the value of s_z is (z+1)(3-z).

(b)

The given arithmetic sequence is

7, 4, 1, ...

We need to find the term in the sequence.

In the given arithmetic sequence the first term is

a=7

The common difference of the sequence is

d=a_2-a_1\Rightarrow 4-7=-3

The first term is 7 and common difference is -3.

Add common difference in last given term, i.e., 1, to find the next term of the sequence.

1+(-3)=1-3=-2

Therefore the next term in the sequence is -2.

3 0
4 years ago
Hey can anyone help please and thank you !
EleoNora [17]

Answer:

x = 2

Step-by-step explanation:

4 0
3 years ago
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HELP PLEASE!
Archy [21]

Answer:

Option 2  50 ≤ s ≤ 100

Option 5 She could deposit $50

Option 6 She could deposit $75

Step-by-step explanation:

Let

s -----> amount of money Layla deposit into a saving account

we know that

25%=25/100=0.25

50%=50/100=0.50

so

s\geq 0.25*200 -----> s\geq \$50

s\leq 0.50*200 -----> s\leq \$100

The compound inequality is

\$50 \leq s\leq \$100

<em>Verify each case</em>

case 1) 25 ≤ s ≤ 50

The statement is false

see the procedure

case 2) 50 ≤ s ≤ 100

<u>The statement is True</u>

see the procedure

case 3) s ≤ 25 or s ≥ 50

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 4) s ≤ 50 or s ≥ 100

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 5) She could deposit $50

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

case 6) She could deposit $75

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

3 0
4 years ago
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Elliot has deposited $723 in a savings account that earns interest at a rate of 2.9% compounded twice a year. What will the acco
Nadusha1986 [10]
A=P(1+r/n)^(nt) where n= number of times compounded yearly, t= time and p= principle

A=723(1+.029/2)^(2*23)

A=$1,401.95   So C
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3 years ago
FIRST ONE TO GET ME THE CORRECT ANSWER WILL WIN BRAINIEST
Dafna11 [192]

9514 1404 393

Answer:

  59 3/4

Step-by-step explanation:

The change from the opening price is ...

  -50 1/2 +110 1/4 = 60 -1/4 = 59 3/4 . . . change from opening price

3 0
3 years ago
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