Answer:
The average number of points this player will get in 100 one-and-one free throw situations is 70.
Step-by-step explanation:
For each free throw, there are only two possible outcomes. Either the player makes it, or he does not. The probability of the player making a free throw is independent of other free throws. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

70% free throw percentage.
This means that 
What is the average number of points this player will get in 100 one-and-one free throw situations?
This is E(X) when n = 100. So

The average number of points this player will get in 100 one-and-one free throw situations is 70.
Answer: I'm pretty sure its 3x+27
Step-by-step explanation: So all you have to do is multiply everything in the parentheses by 3. So you would do 3 times x and it would be 3x and then 3 times 9 which will get you 27. After you just put it back into a equation 3x+27
For Question 1 the answer is the last choice.
#1. 712.5
#2. 1185
#3 .517.5
That person;s body weight will be 156 Ib. Do 9 3/4 times 1/16 to get you body weight