The cell potential for an electrochemical cell with a Zn, Zn2 half-cell and an Al, Al3 half-cell is _____ V. Enter your answer t
1 answer:
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Answer:
Explanation:
The alkene reactions in general are addition or oxidation reactions. For the addition reaction, we have to take into account that some of them are marknonikov and other anti-markovnikov. Also for the addition reaction, we will have to take into account if we will have anti or syn products. In the oxidation reaction, we have to know the specifics for each reaction. If the reaction can go to the highest oxidation level, is the double bond is broken, etc.
Each reaction has its <u>specific characteristics</u> (see figures 1 and 2).
The answer is (A.) 135.6 N
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Here is the formula you will need to answer the question.
Formula:
Force(N) = Mass(kg) x Acceleration(m/s²)
or... F(N) = m(kg) x a(m/s²)
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We need to be certain of the information presented. The problem says the man has a "Mass" of 83 kilograms on Earth. If a man has a Mass of 83 kilograms on Earth, he has a mass of 83 kilograms everywhere. The mass for this problem (even on the moon) is 83.
Mass(kg): 83
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To find the acceleration of object on other planets, moons, ect, you'll need to search the internet or ask a teacher. There are ways to calculate this, but the problem didn't supply the necessary information to do so.
Acceleration: 1.625 m/s²
————
Now just plug the information into the formula.
F(N) = m(kg) x a(m/s²)
N = 83 x 1.625
N= 135.875
When considering that there could be a slighty more accurate number for acceleration, it can be concluded that the best answer is (A.)
————
Here is the formula you will need to answer the question.
Formula:
Force(N) = Mass(kg) x Acceleration(m/s²)
or... F(N) = m(kg) x a(m/s²)
————
We need to be certain of the information presented. The problem says the man has a "Mass" of 83 kilograms on Earth. If a man has a Mass of 83 kilograms on Earth, he has a mass of 83 kilograms everywhere. The mass for this problem (even on the moon) is 83.
Mass(kg): 83
————
To find the acceleration of object on other planets, moons, ect, you'll need to search the internet or ask a teacher. There are ways to calculate this, but the problem didn't supply the necessary information to do so.
Acceleration: 1.625 m/s²
————
Now just plug the information into the formula.
F(N) = m(kg) x a(m/s²)
N = 83 x 1.625
N= 135.875
When considering that there could be a slighty more accurate number for acceleration, it can be concluded that the best answer is (A.)