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Maksim231197 [3]
2 years ago
8

Calculate the percent composition of hydrogen in C8H9NO2.

Chemistry
1 answer:
oee [108]2 years ago
6 0

Answer:

72.72%

Explanation:

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Write an equation for the hydrogenation of glyceryl trilinolenate, a fat formed from glycerol and three linolenic acid molecules
Tomtit [17]

Balanced chemical equation for the hydrogenation of glyceryl trilinolenate:

C₅₇H₉₂O₆ + 9H₂ → C₅₇H₁₁₀O₆.

Linolenic acid (octadecatrienoic acids ) is a type of fatty acid. It has 18 carbon atoms chain and three double bonds. So trilinolenate has nine double bonds.

Trilinolenate is the form of triglyceride esters of linolenic acid.

Hydrogenation is addition of hydrogen atoms at both sides of a double bond.

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4 years ago
Differentiate between Mendeleev's Period law and Modern Periodic law<br>​
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<h2>see in the attachment hope it helps you</h2>

7 0
3 years ago
3.15.8 cm3 of H2SO4 completely neutralised 20 cm3 of NaOH. The NaOH was 1.5 mol/dm3.
Furkat [3]

Answer:

Molarity = 0.95 mol/dm³

Explanation:

Given data:

Volume of H₂SO₄ = 15.8 cm³

Volume of NaOH = 20 cm³

Concentration of NaOH = 1.5 mol/dm³

Concentration of H₂SO₄ = ?

Solution:

Chemical equation:

NaOH + H₂SO₄      →          Na₂SO₄ + H₂O

First of all we will calculate the number of moles of NaOH and for that we will convert the units first,

Volume = 20 cm³/1000 = 0.02 L

Concentration of NaOH = 1.5 mol/dm³

1 mol/dm³ = 1 mol/L

Concentration of NaOH = 1.5 mol/L

Number of moles of NaOH:

Molarity = number of moles / volume in L

1.5 M = number of moles / 0.02 L

Number of moles = 1.5 M ×0.02 L

Number of moles = 0.03 mol

Now we will compare the moles of NaOH and H₂SO₄

                     NaOH           :        H₂SO₄

                         2               :           1

                     0.03             :        1/2×0.03 = 0.015 mol

Concentration of H₂SO₄:

Volume of H₂SO₄:

15.8 cm³/1000 = 0.0158 L

Molarity = number of moles / volume in L

Molarity = 0.015 mol / 0.0158 L

Molarity = 0.95 mol/L

1 mol/L = 1 mol/dm³

Molarity = 0.95 mol/dm³

6 0
3 years ago
Which of the following is the first stage of the photo-independent reaction?
AVprozaik [17]
Carbon source is the answer for ur question
8 0
3 years ago
How does reducing the temperature of chemical reaction affect the rate at which it occurs?
Licemer1 [7]

Answer:

When you lower the temperature, the molecules are slower and collide less. That temperature drop lowers the rate of the reaction. When you increase the pressure, the molecules have less space in which they can move. That greater density of molecules increases the number of collisions.

Explanation:

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If u can...

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6 0
3 years ago
Read 2 more answers
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