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Pie
3 years ago
7

A number N is greater than 3. Which of the following best represents the location of

Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0
N>3, so 1/N would be 1/(>3)
which makes it < 1/3
and 1/3 < 1 so it should be between 0 and 1 in the number line, closer to 0 than 1.
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Josef has 35 square feet of tiles. He cuts 15 of those tiles in half. How many square feet of tiles does Josef have now? Explain
Tanya [424]

Answer:

50

Step-by-step explanation:

35 +15 =50  15 dived by 2 = 7.5 x 2 =15 + 35 = 50

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3 years ago
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A solid cylindrical metal is melted and recast into cubes of metal of sides 3cm . The base radius of the initial cylindrical met
Orlov [11]

Answer:

Approximately 809 cubes will be made

Step-by-step explanation:

To calculate the number if cubes to be made, we shall need to calculate the volume of both shapes

The volume of the cubes can be calculated using the formula L^3 = 3 * 3 * 3 = 27 cm^3

For the cylinder, the formula of the volume to use is

V = π * r^2 * h

The radius here is 10.5 cm and the height is 63 cm

V = 22/7 * 10.5^2 * 63 = 21,829.5 cm^3

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That is 21,829.5/27 = 808.5 which is 809 to the nearest whole number

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3 years ago
By first calculating the size of angle LMN,
Naily [24]

Step-by-step explanation:

Hope it helps.... that is how I did it

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3 years ago
Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
Oksanka [162]

Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

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3 years ago
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