0.049, 0.08, 0.1, 0.103, 1.8.
A car dealership pays the sum of $8,350 for a car
The dealer mark up the car price by 17.4%
The retail price = Mark up percentage x original price of the car
Mark up = 17.4%
= 17.4 + 10
= 117.4%
Convert 117.4% to decimal
= 117.4/100
= 1.174
The retail price = $8, 350 x 1.174
= $9,802.90
The retail price of the car is $9,802.90
Answer:
Hence the probability of the at least 9 of 10 in working condition is 0.3630492
Step-by-step explanation:
Given:
total transistors=100
defective=20
To Find:
P(X≥9)=P(X=9)+P(X=10)
Solution:
There are 20 defective and 80 working transistors.
Probability of at least 9 of 10 should be working out 80 working transistors
is given by,
P(X≥9)=P(X=9)+P(X=10)
<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>
P(X≥9)=
<em>(Use the permutation and combination calculator)</em>
P(X≥9)=(231900297200*20/17310309456440)
+(1646492110120/17310309456440)
P(X≥9)=0.267933+0.0951162
P(X≥9)=0.3630492
Answer:
2x^2/3yz^7
Step-by-step explanation:
Answer:
129.99
Step-by-step explanation:
129.99 rounds to 130 because the 9 in the hundredths place causes the 9 in the tenths place to round up, making the number 130.0.