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3 years ago

Subtract

Mathematics

1 answer:

kirza4 [7]3 years ago

5 0

Answer:

Option D: 3x2 + 2x - 1

Step-by-step explanation:

Given that:

=(5x2 - 5x + 3 )- (2x2 +7x- 4)

As we have to subtract them so by simplifying:

"-" sign will alter all signs in the bracket

= 5x2 - 5x + 3 - 2x2 + 7x - 4

Now by adding same terms

= 5x2 - 2x2 - 5x + 7x + 3 -4

= 3x2 + 2x - 1

i hope it will help you!

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PLEASE TAP ON THE PHOTO I NEED HELP ASAP

d1i1m1o1n [39]

5, 3, -5, -1

-2x-1 = 2+3= 5

-2x0 = 0+3= 3

-2x1 = -2+3= -5

-2x2 = -4+3= -1

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2 years ago

In a chess tournament, each player is in one game with every other player. How many games will be played if there are 7 players

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3 years ago

What is the slope for (3,-4) (5,-4)

alina1380 [7]

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{3}}}\implies \cfrac{-4+4}{2}\implies \cfrac{0}{2}\implies 0$

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3 years ago

How do we get an<br> equation in slope-intercept form?

Viefleur [7K]

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y = mx + b

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3 years ago

One of the roots of the equation 3x^2+7x−q=0 is −5. Find the other root and q.

statuscvo [17]

Answer: The answer is $\textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation: The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.$

Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.

Let the other root of the equation be 'p'. So, we have

$p-5=-\dfrac{7}{3}\\\\\\\Rightarrow p=5-\dfrac{7}{3}\\\\\\\Rightarrow p=\dfrac{8}{3},$

and

$p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.$

Thus, the other root is $\dfrac{8}{3}$ and the value of 'q' is 40.

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3 years ago