Answer:
x = 17
Step-by-step explanation:
These angles are supplementary so (2x + 5) + (8x = 5) = 180 then you just do the algebra
Please mark Brainliest :)
Answer:
a.
b.
Step-by-step explanation:
Dimensions of rectangular piece of cardboard=
According to question
Length of box,l=10-2x
Breadth of box,b=6-2x
Height of box,h=x
a.
Volume of box=
Substitute the values in the formula
Volume of box=
b.Surface area of box=
Because the box has no lid
Substitute the values in the formula
Surface area of box=
Surface area of box=
Surface area of box=
Surface area of box=
Surface area of box, S(x)=
Answer:
Option b is the correct answer
Step-by-step explanation:
The graph in the picture is the graph of a quadratic equation and it takes the shape of a parabola.
The points on the x axis through which the parabola cuts across is used to determine the solution of the quadratic equation.
Looking at the parabola formed from the plotted points, it cuts the x axis at
x = -1 and x= -2
These are the factors of the equation. To get the equation, we multiply the factors.
x= -1, x +1 = 0
x =-2 , x + 2= 0
The equation is (x+1)(x+2)
Expanding the brackets,
x×x + x×2 +1×x + 1×2
= x^2 + 2x + x +2
= x^2 + 3x +2 = 0
Option b is the correct answer
It would be 7.54 because you fist have to put the numbers ordered smallest to biggest amount 7.15, 7.44, 7.48,7.60, 7.72, 7.73 so the numbers that are in the middle are 7.48 and 7.60 you add them up, and the result you divide by 2 which gives you 7.54.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
