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mote1985 [20]
3 years ago
10

Can some one help me pls

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0
E. 5/15 since you multiply the numerator and denominator by 5.

D. 2/3 since you divide the numerator and denominator by 3.

W. 15/24 since you multiply the numerator and denominator by 3.

J. 4/5 since you divide the numerator and denominator by 5.

C. 48/54 since you multiply the numerator and denominator by 6.

G. 24/21 since you multiply the numerator and denominator by 3.

T. 27/36 since you multiply the numerator and denominator 3.
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Marvin wants to purchase a rectangular rug. It has an area represented by the expression 4x^2+64x+256. what is the length and wi
jasenka [17]

Answer: the length and width are

(x + 8) and (x + 8)

Step-by-step explanation:

The rug has an area represented by the expression

Area = 4x² + 64x + 256.

The factors in the factored expressions represent the length and width of the rug.

Dividing the the equation by 4, it becomes

x² + 16x + 64 = 0

We would find two numbers such that their sum or difference is 16x and their product is 64x^2.

The two numbers are 8x and 8x. Therefore,

x² + 8x + 8x + 64 = 0

x(x + 8) + 8(x + 8) = 0

The factors are

(x + 8)(x + 8)

7 0
3 years ago
Hello! Can you please help me on these two problems? =)
poizon [28]

Yeah, I gotta read the questions better.

Perimeter not area.

diagonal length = √((28 - 12)² + (24 - 10)²) = 21.26

P = 12 + 10 + 28 + 24 + 21.26 = 95.26 units

sphere surface area = 4πR²

R = √(379.94 / 4(3.14) = 5.5 in

D = 2R = 11 inch

4 0
3 years ago
Simplify.... Please, I really need help.
Brilliant_brown [7]

Answer:

Step-by-step explanation:

Note that 128 = 64*2.  The square root of 128 is thus 8sqrt(2).  Answer B is the only one that could be correct.

7 0
3 years ago
Without using a calculator determine the number of real zeros of the function f(x) = x^3 + 4x^2 + x -6
hodyreva [135]
Try this:
x³+4x²+x-6=0
1) To re-write the equation into form:
1*x³+4*x²+1*x-6=0, the note 1+4+1=6, it means x=1
2) to re-write the equation into form:
(x-1)(x²+5x+6)=0
(x-1)(x+2)(x+3)=0
3)
\left[\begin{array}{ccc}x-1=0\\x+2=0\\x+3=0\end{array}\right \ \ \textless \ =\ \textgreater \   \left[\begin{array}{ccc}x=1\\x=-2\\x=-3\end{array}\right
Answer: -3;-2;1.
8 0
3 years ago
Solve five ninths minus two sixths
Fittoniya [83]
The answer would be 12/54 (twelve fifty fourths) but if you simplify it you would get 2/9 (two ninths).
4 0
3 years ago
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