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luda_lava [24]
3 years ago
12

Pls help me answer this :(

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0
Eek let me get my bother
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How do I solve this?
Ghella [55]
The product of the two segments from the two chords are equal.

4(4+5)=(x-2)(x-2+x+4) or 36=(x-2)(2x+2) or x^2-x-20=0 or (x-5)(x+4)=0

So x=5.
8 0
3 years ago
What is 787.526 rounded to the nearest tenths A; 787.6 B; 787.0 C; 787.5
sasho [114]

Answer:

I believe it's <em>C</em>

Step-by-step explanation:

4 or less let it rest 5 or more go next door I think is how it goes lol

forgot to explain: 6 is more than 5 so we add one to the next place. that makes 2 + 1 which is 3 and 3 is less than 4 so we don't add to the next place.

7 0
3 years ago
Read 2 more answers
PLSSSSSSSSSSSSSS HELPPPP MEEEEEEE! ANSWER MY OTHER QUESTION!!!!
butalik [34]

Answer:

Step-by-step explanation:

huh??

6 0
3 years ago
Help pleaseeeee????????????
gogolik [260]

Answer:

y = 107 z = 73 x = 73

Step-by-step explanation:

Y and 107 are the same angle 107 + 73 = 180

4 0
2 years ago
Can someone pls help me find the second derivative of this. I need to find the concave up and down intervals but I’m having trou
KonstantinChe [14]

Starting from

f(x)=\dfrac14(x+1)^{\frac83}-4(x+1)^{\frac23}

take the first derivative using the power and chain rules:

f'(x)=\dfrac83\cdot\dfrac14(x+1)^{\frac83-1}-\dfrac23\cdot4(x+1)^{\frac23-1}

f'(x)=\dfrac23(x+1)^{\frac53}-\dfrac83(x+1)^{-\frac13}

Now take the second derivative:

f''(x)=\dfrac53\cdot\dfrac23(x+1)^{\frac53-1}-\left(-\dfrac13\right)\cdot\dfrac83(x+1)^{-\frac13-1}

f''(x)=\boxed{\dfrac{10}9(x+1)^{\frac23}+\dfrac89(x+1)^{-\frac43}}

Optionally, you can condense the second derivative a bit by factoring out \frac89(x+1)^{-\frac43}, which gives

f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^{\frac63}+1\right)

f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^2+1\right)

f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80x^2+160x+81\right)

3 0
3 years ago
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