Answer:
y=3/2x-6
Step-by-step explanation:
To find the y=mx+b you need to move the y on one side while moving the others on the other side
First, move the 3x to the other side by subtracting by 3x on both sides:
-2y=-3x+12
Divide by -2 on both sides:
y=3/2x-6
Answer:
h= 9.473684 in.
Step-by-step explanation:
1/2(8)(15)*2+2(15h)+8h=480
120+38h=480
38h=480-120
38h=360
h= 9.473684 in.
Answer: -9n+20
This is the same as 20-9n
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Explanation:
The jump from 11 to 2 is "minus 9"
The jump from 2 to -7 is also "minus 9".
Assuming this pattern continues on, we have an arithmetic sequence with
- a = 11 = first term
- d = -9 = common difference
The nth term can be found like so
Let's check the answer by trying n = 3
This shows the third term is -7, which matches what the original sequence shows. The answer is partially confirmed. I'll let you check the other values of n. You should get 11 when trying n = 1, and you should get 2 when trying n = 2.
Answer:
B. 2 is your answer
Step-by-step explanation:
You will use the slope formula to find the slope of the equation.
(3, 7) and (-2, -3) will be used.
7 and -3 are your y's. 3 and -2 are your x's.
(7 - (-3))/(3 - (-2)) = 10/5 = 2
B. 2 is your answer
If you mean "factor over the rational numbers", then this cannot be factored.
Here's why:
The given expression is in the form ax^2+bx+c. We have
a = 3
b = 19
c = 15
Computing the discriminant gives us
d = b^2 - 4ac
d = 19^2 - 4*3*15
d = 181
Note how this discriminant d value is not a perfect square
This directly leads to the original expression not factorable
We can say that the quadratic is prime
If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.
