The quick way to dispute something like this is to simply do the calculation and then create a ratio.
Cube One (Large Cube)
The formula for a cube is V = e^3
e = the measurement of an edge. In this case.
e = 10 cm
V = e^3
V = 10^3 = 10*10*10
V = 1000 cm^3
Cube 2 (Small Cube)
V = e^3
e = 5 cm
V = 5*5*5
V = 125 cm^3
Ratio
Large Cube / Small Cube = 1000 / 125 = 8/1.
The difference in size is 8 to 1 not 2 to 1.
Explanation
He's right if he sticks to one side. The ratio of one side of the large cube to the small one is 2 to 1. But once you put that into the formula for volume, three sides are multiplied together and that 2 shows up everytime you multiply the sides together.
Answer:
y= b+ 3a
Step-by-step explanation:
Given data
We are required to rent a bike and a helmet
le the flat fee for bike rental be a
and the flat fee helmet be b
let the number of hours be h
and let the total cost be y
So
y= b+ah
for h = 3
tThen the expression for the total is given as

Answer: the answer is 0.125 foot per square foot
Step-by-step explanation:
15*6=90 hours
90 *8.25=742.50
Your answer would be $742.50. Hope it helps!
Answer:
The area can be written as

And the value of it is approximately 1.8117
Step-by-step explanation:
x = u/v
y = uv
Lets analyze the lines bordering R replacing x and y by their respective expressions with u and v.
- x*y = u/v * uv = u², therefore, x*y = 1 when u² = 1. Also x*y = 9 if and only if u² = 9
- x=y only if u/v = uv, And that only holds if u = 0 or 1/v = v, and 1/v = v if and only if v² = 1. Similarly y = 4x if and only if 4u/v = uv if and only if v² = 4
Therefore, u² should range between 1 and 9 and v² ranges between 1 and 4. This means that u is between 1 and 3 and v is between 1 and 2 (we are not taking negative values).
Lets compute the partial derivates of x and y over u and v




Therefore, the Jacobian matrix is
and its determinant is u/v - uv * ln(v) = u * (1/v - v ln(v))
In order to compute the integral, we can find primitives for u and (1/v-v ln(v)) (which can be separated in 1/v and -vln(v) ). For u it is u²/2. For 1/v it is ln(v), and for -vln(v) , we can solve it by using integration by parts:

Therefore,
