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Pavel [41]
3 years ago
12

Hi! I have an math exam tomorrow and I really need you guys help.

Mathematics
1 answer:
qaws [65]3 years ago
8 0
I think the answer is 37
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Plz help me asap. Plz help help help
Leya [2.2K]
The answer is 10 because 9x5=45 then you do 45-15=30 then you divide by 3 which is 10.
Your welcome
5 0
3 years ago
2/3 4/5 3/4 1/8 put in order from greatest to least
m_a_m_a [10]
2/3, 4/5, 1/8 is the correct order from greatest to least.
3 0
3 years ago
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How to find the area
Virty [35]

Just like you drew those dotted lines. You know how to find the areas of rectangles which is A=length x width

The answer would be 20cm^2+6cm^2+18cm^2=44 cm^2


7 0
4 years ago
Read 2 more answers
Calculate area of triangle
Radda [10]

Answer:

60cm^2

Step-by-step explanation:

15 times 8 = 120

divided by 2  = 60

3 0
3 years ago
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Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .
stich3 [128]

\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}


\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
\\\\\\
\cfrac{8^2}{7^2}\implies \cfrac{64}{49}

4 0
4 years ago
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