No entiendo nada por favor explícame
A perpendicular bisector
this means the length IJ=JK and the angles IJB, BJK are 90° (and their congruent angles too)
but this does not mean AB=IK, because their lengths can be arbitrary
for a similar reason AJ=IJ is wrong, essentially the same statement but with half lengths
BI=BK is true, because it is a bisector of IK this means the sides IJ=JK and JB is a shared side, therefore also having the same length. We also know IJB and BJK are congruent angles, so all in all these are congruent triangle and therefore also share the side length
BI=AK is false, because we don't know where the intersection point j is on AB, it could split the length into any arbitrary ratio, in case these are two equal sides then it would be true, but it doesn't hold for all other possibilities
so BI=BK is the solution
Answer:
Yes, they are equal in the values (in radians):
π/4, 5π/4
If cos(x) and sin(x) are defined to you as nonnegative functions (in terms of lengths), then 3π/4 and 7π/4 are also included
Step-by-step explanation:
Remember that odd multiples of 45° are special angles, with the same sine and cosine values (you can prove this, for example, by considering a right triangle with an angle of 45° and hypotenuse with length 1, and finding the trigonometric ratios).
The radian measure of 45° corresponds to π/4, hence the odd multiples on the interval [0, 2π) are π/4, 3π/4, 5π/4, 7π/4.
If you define sin(x) and cos(x) using the cartesian coordinate system (via unit circle), then cos(3π/4)=-sin(3π/4) and cos(7π/4)=-sin(7π/4). In this case, only π/4 and 5π/4 are valid choices.
Answer:
yes Amen and we also need Jesus
Step-by-step explanation:
The binomial distribution is given by,
P(X=x) =
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) =
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) =
+
+
+
+
+
+
Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.
