It would be 20, since you’re replacing the x value with 2. 10(2) is 20.
The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y=
...........(eq iii)
Substitute the value of y into eq i
x-(
= k
x- (
= k
k= 
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So what you do,is you add them together to get 13/10 but then you can also simplify it but you can keep the answer to 13/10
X = mia's score
eric scored 10 more then mia....so eric's score is x + 10
isabella scored 16 less then twice mia's score...so isabells's score is 2x - 16
so the expression x + x + 10 + 2x - 16 is a total of all 3 people's scores combined
Answer:
see below
Step-by-step explanation:
1. 0 = (r + 1)(r + 8)
Using Zero Product Property, r = -1, r = -8
2. h(r) = (r + 1)(r + 8)
= r² + 9r + 8
= (r + 9/2)² - 81/4 + 8
= (r + 4.5)² - 12.25 (Complete the square)
Vertex: (-4.5, -12.25)