Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
It will equally 2 because you need to change the 3 into a 9 because you can't add fractions without having the same common demometer
Step-by-step explanation:
Answer:
The graph's vertex would move 4 to the right and would become twice as wide.
Step-by-step explanation:
We can tell this because the x value of the vertex is the constant inside the parenthesis. In this case, the number changes from 11 to 15, which means it moves to the right by 4.
And with the 2 outside of the parenthesis instead of inside, it becomes more wide (since the 2 is not being squared).
Answer:
i have
Step-by-step explanation:
said what
Answer:
<h2>Infinitely many solutions</h2>
Step-by-step explanation:
