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4 years ago

What volume of water is needed to dilute 10.0 mL of 2.0 M HCl to make a 0.25 M HCl solution?

Mathematics

2 answers:

Nikolay [14]4 years ago

7 0

The answer for that would be D. 80 mL

tresset_1 [31]4 years ago

5 0

Answer:

D. 80 mL

Step-by-step explanation:

Given:

- 10.0 mL of HCL

- 2.0 M HCl

- .25 M HCl

1) Convert mL to L

10 mL/1000 mL = .01 L

2) Find # of moles of HCl

2.0 M HCl = (x/.01 L)

x = .02 mol HCl

3) Find volume needed to make .25 M HCl

.25 M = .02 mol HCl/ y

y = .08 Liters

4) Convert Liters to mL

.08 L * 1000 mL = 80 mL

Answer: 80 mL (D)

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Find the measure of DC if m

kupik [55]

Answer:

B. 132°

Step-by-step explanation:

<u>Find the measure of arc BD</u>

m∠A = 1/2(arc BC - arc BD)
2*36° = 150° - arc BD
arc BD = 150° - 72° = 78°

<u>Find the measure of arc DC</u>

arc BD + arc BC + arc DC = 360°

arc DC = 360° - (150° + 78°) = 360° - 228° = 132°

Correct choice is B

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3 years ago

When the county fair opened its gates, 68 people entered the fairgrounds. After one hour, there were 1.5 times as many people on

pickupchik [31]

Answer:

y=68(1.5)^(x-1)

Step-by-step explanation:

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3 years ago

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A local aquarium purchased a new turtle tank for their giant turtle exhibit. What is the volume of the turtle tank. 15 yd, 12yd,

slavikrds [6]

Answer:

1440 yd³

1200 yd³

Step-by-step explanation:

A local aquarium purchased a new turtle tank for their giant turtle exhibit for their giant turtle exhibit.

By using the dimensions 15yd by 12yd by 8yd and the shape of the tank is cubooid

We can determine volume by using the formula i.e

V = (Length) × (Width) × (Height),

then the volume of the tank will be

V = 15 × 12 × 8 =

V=1440 yd³.

Now , by using dimensions 15 yd by 8 yd by 10 yd

The volume will be,

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6 0

3 years ago

Solve the triangle. Round your answers to the nearest tenth. A. m∠A=43, m∠B=55, a=16 B. m∠A=48, m∠B=50, a=23 C. m∠A=48, m∠B=50,

alexgriva [62]

Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

$\frac{sin(B)}{b} = \frac{sin(C)}{c}$

$\frac{sin(B)}{24} = \frac{sin(82)}{29}$

$sin(B)*29 = sin(82)*24$

$\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}$

$sin(B) = \frac{sin(82)*24}{29}$

$sin(B) = 0.8195$

$B = sin^{-1}(0.8195)$

$B = 55.0$

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

$\frac{a}{sin(A)} = \frac{b}{sin(B)}$

$\frac{a}{sin(43)43} = \frac{24}{sin(55)}$

Cross multiply

$a*sin(55) = 25*sin(43)$

$a = \frac{25*sin(43)}{sin(53)}$

$a = 20$ (approximated)

8 0

3 years ago

If f(x) =3x^2 + 1 and g(x)=1-x

motikmotik

Answer: f ( 1 − x ) = 3 x 2 − 6 x + 4

Your WElcome

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3 years ago

Read 2 more answers