Answer:
length: 16 m; width: 13 m
Step-by-step explanation:
Write each of the statements as an equation. You know that the formula for the perimeter is ...
P = 2(L +W)
so one of your equations is this one with the value of P filled in:
• 2L + 2W = 58
The other equation expresses the relation between L and W:
• L = W +3 . . . . . . . . the length is 3 meters greater than the width
There are many ways to solve such a system of equations. Since you have an expression for L, it is convenient to substitute that into the first equation to get ...
2(W+3) +2W = 58
4W +6 = 58 . . . . . . . simplify
4W = 52 . . . . . . . . . . subtract 6
W = 13 . . . . . . . . . . . .divide by 4
We can use the expression for L to find its value:
L = 13 +3 = 16
The length is 16 meters; the width is 13 meters.
Answer:
11060.83
Step-by-step explanation:
Sum = 10000 + 10250 + 10790 + 9865 + 15350 + 10110
= 66365
No. of days (N) = 6
Arithmetic mean = Sum/ N
= 66365/6
= 11060.83
Answer:
The rate of change of the tracking angle is 0.05599 rad/sec
Step-by-step explanation:
Here the ship is traveling at 15 mi/hr north east and
Port to Radar station = 2 miles
Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles
Therefore the ship, port and radar makes a triangle with sides
2, 7.5 and x
The value of x is gotten from cosine rule as follows
x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04
x = 6.25 miles
By sine rule we have
Therefore,
α = Angle between radar and ship α
∴ α = 58.052
Where we put
to get
and differentiate to get
= 3.208 degrees/second = 0.05599 rad/sec.
Answer:
E
Step-by-step explanation:
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