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2 years ago

Find the area of the semicircle

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

7 0

Answer:

Area of semicircle =( π r2)÷ 2

= 1/2 × 22/7 × 11 ×11

= 11 × 17.5

= 19.25 CM2

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Last year 500 people attended a concert this year 900 people attended what was the percent increase in attendance from last year

IRISSAK [1]

Answer:

Step-by-step explanation:

500 to 900? = 80.

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3 years ago

Select all the rates equivalent to the rate 3/4 cup per pound

Artemon [7]

Answer:

Step-by-step explanation:

Multiply the decimal by 100 and write the result with the percentage sign: 0.75 × 100 = 75%.

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2 years ago

Determine the equation of the line that goes through points (1.1) and (3.7).

ValentinkaMS [17]

Answer:

The equation of the line that goes through points (1,1) and (3,7) is $\mathbf{y=3x-2}$

Step-by-step explanation:

Determine the equation of the line that goes through points (1,1) and (3,7)

We can write the equation of line in slope-intercept form $y=mx+b$ where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=1, y_1=1, x_2=3, y_2=7$

Putting values and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{7-1}{3-1}\\Slope=\frac{6}{2}\\Slope=3$

We get Slope = 3

Finding y-intercept

y-intercept can be found using point (1,1) and slope m = 3

$y=mx+b\\1=3(1)+b\\1=3+b\\b=1-3\\b=-2$

We get y-intercept b = -2

So, equation of line having slope m=3 and y-intercept b = -2 is:

$y=mx+b\\y=3x-2$

The equation of the line that goes through points (1,1) and (3,7) is $\mathbf{y=3x-2}$

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3 years ago

The circumference of a circle is 25.12cm. What is the area of the circle? Use 3.14

malfutka [58]

C=2pir
area=pir^2

given
c=25.12
25.12=2pir
pi=3.14
25.12=2(3.14)r
25.12=6.28r
divide both sides by 6.25
4=r

sub into other
area=pir^2
area=pi4^2
area=16pi
area=16(3.14)
area=50.24

the area is 50.24 square cm

3 0

3 years ago

Please help! Need em doneee

kogti [31]

Letter C

Use the Distance formula
sq rt [ (x2 - x1)^2 + (y2 - y1)^2 ]

sq rt [ (10-5)^2 + (2 - 4)^2 ]
sq rt [ (5)^2 + (-2)^2 ]
sq rt ( 25 + 4)
Square root of 29

6 0

10 months ago

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