I am rocking with C. Jasmine left class for head.
if im wrong let me know
Step-by-step explanation:
Recall the Ratio for tan
Tan(theta) = opposite / adjacent
Tan (x) = 9 / 5
solve for x (use Tan^-1(...) )
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
