Answer:
Correct arrangement of equation of displacement to find a is as follows;
1- Vt - d = 1/2 a t^2 (^ represents exponent i.e. t square as given in equation)
2- 2(Vt - d ) = a t^2
3- a = 2(Vt - d )/ t^2 (keep in mind, 2(Vt - d) whole divided by t^2)
Step-by-step explanation:
1- In the first equation, Vt is taken to the left side of the equation (keep in mind, original equation of displacement used for reference as given in question) and multiplied by -1 on the both sides of the equation.
2- In the second equation, 2 is multiplied on the both sides.
3- Multiply t^2 on both sides of the equation, We will get a in correct arrangement, which is required to find.
Answer:
A standard deck of cards has four suites: hearts, clubs, spades, diamonds. Each suite has thirteen cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen
Answer:
If 
whenever 
f is <em>increasing</em> on I.
If 
whenever f is <em>decreasing</em> on I.
Step-by-step explanation:
These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:
When you choose any two numbers on I and compare their image under f, the following can happen.
- . Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
- . The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.
Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.
Answer:
3rd answer down
Step-by-step explanation:
ok so you take the median of all the #'s which turns out to be 126.5 and that is where your bar should point to in the box, then you should start with 105, and your last bit of the line should end at 150, the start of your box should start at the median of 105 and 117, and the end of your box should stop at the median of 145 and 150.
