Express 1.347 as a repeating decimal

Which equations are true for x = –2 and x = 2? Check all that apply.

4vir4ik [10]

А. х²-4=0; х²=4; х=±2, true. B. x²=-4; there is no solution. C. 3x²+12=0; 3x²=-12; x²=-4; there is no solution. D. 4x²=16; x²=4; x=±2, true. E. 2(x-2)²=0; 2(x²-4x+4)=0; 2x²-8x+8=0; x²-4x+4=0; x1=2; x2=2. False. The answer: A, D.

4 0

2 years ago

You save for retirement over 30 years by investing $850/month in a stock account that yields 10%. You invest $350/month in a bon

sergejj [24]

Answer:

$13,287.70

Step-by-step explanation:

The future value of the stock account is computed as the sum of a geometric series. This computation assumes that the annual yield is compounded monthly.

FV = p((1+r/12)^(12n) -1)/(r/12)

For the stock account, p=850, r=0.10, n=30, so the future values is ...

FV = 850((1+.10/12)^360-1)/(.10/12)) = 1,921,414.74

For the bond account, p=350, r=.06, n=30, so the future value is ...

FV = 350((1+.06/12)^360 -1)/(.06/12) = 351,580.26

The combined account value at the end of 30 years is ...

$1,921,414.74 + 351,580.26 = $2,272,995.00

_____

The monthly payment that can be made over a 25 year period is given by the amortization formula.

A = P(r/12)/(1 -(1 +r/12)^(-12n))

= $2,272,995.00(.05/12)/(1 -(1+.05/12)^-300) = $13,287.70

You can withdraw $13,287.70 each month assuming a 25-year withdrawal period.

6 0

3 years ago

Work out the size of angle x

mestny [16]

Answer:

97 degrees

Step-by-step explanation:

5 0

2 years ago

On a trip, Duke encounters some road construction that slows him down. While he is able to go 60 mph on the highway and 40 mph t

natulia [17]

Answer:

Time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

Step-by-step explanation:

Speed by which Duke travels a distance on highway $d_1$ = 60 mph

Let the time taken to travel on highway = $t_1$ hours

Distance traveled = $60t_1$ miles

Speed in the city = 40 mph

Let the time taken = $t_2$ hours

Distance traveled in the city = $40t_2$ miles

Speed on the construction = 20 mph

Let the time spend on the construction = $t_3$ hours

Distance traveled on the construction = $20t_3$ miles

Since, total distance covered = 380 miles

$d_1+d_2+d_3=60t_1+40t_2+20t_3$

He spends one half the time on the highway as he does on the construction,

$t_3=2t_1$

Total time spent in the trip = 11 hours

Therefore, $t_1+t_2+t_3=11$

$t_1+t_2+2t_1=11$

$t_2=11-3t_1$

From equation (1),

$60t_1+40(11-3t_1)+20(2t_1)=380$

$60t_1-120t_1+40t_1+440=380$

$440-20t_1=380$

$20t_1=440-380$

$t_1=\frac{60}{20}$

$t_1=3$ hours

$t_2=11-3t_1=2$ hours

$t_3=2t_1=6$ hours

Therefore, time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

3 0

2 years ago

Can u help me with my workk

eimsori [14]

You knew where to place the target based on the coordinates (-5,4). Starting from the origin (0,0), we know how many units to move to horizontally and vertically. We move the target 5 units to the left, because it is negative. We move the target 4 units up, because it is positive. (x,y)

6 0

2 years ago