Since there is no denominator or anything under a square root, which are the two limits to domain, your domain would be (-infinity, infinity), and your range would be (-infinity, infinity)
What exactly is your question?
Answer:
f(x)= (x-3)^2-3
Step-by-step explanation:
Vertex Form: y= a(x-h)^2+k
a is the reflection
h and k are the vertex so in an ordered pair (x,y) = (h,k)
Since it is translating 3 units down it is going to be a negative 3. If it was translating up it would be positive 3. This represents the "k" because it is moving on the y-axis.
Since it is translating 3 units to the right it is going to be positive 3. If it was translating left it would be negative 3. This represents the "h" because it is moving on the x-axis.
After plugging it into the vertex form formula: f(x)= (x-3)^2-3
*notice when I plugged the "h" in it became negative because x-(3)= x-3*
64 is the answer to your question
