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Kisachek [45]
3 years ago
12

The main difference between a chest and a bounce pass is what?

Physics
2 answers:
wlad13 [49]3 years ago
6 0

Answer:

The main difference is: the chest pass is straight through the air towards your teammate. While the bounce pass is directed toward the ground and then at your teammate.

The secondary main difference is the amount of power from the ball recived from the person reciving

snow_lady [41]3 years ago
4 0

Answer: The main difference between the three is the mode of transmission. The chest pass is straight through the air towards your teammate. While the bounce pass is directed toward the ground and then at your teammate. Finally, the overhead pass is projected high in the air to avoid defenders.

Explanation:

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Consider two positively charged particles, one of charge q₀ (particle 0) fixed at the origin, and another of charge q₁ (particle
docker41 [41]

Answer:

Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by

F=k\frac{q_0q_1}{r^2}

where r is the distance between the charges & k is the Coulomb's constant

k=1/(4*ε_0*π)

k=9*10^9

the distance between the charges in this question is d_1

hence the magnitude of the force exerted by q_0 on q_1 is given by

F=k\frac{q_0q_1}{d_1^2}

due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form

F=k\frac{q_0q_1}{d_1^2} j

4 0
3 years ago
How do the individual forces compare when the rider experiences a sensation being lighter than his normal weight ? What is the a
shusha [124]

Answer:

When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.

Explanation:

A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.

Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.

When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma

When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma

However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg

When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0

6 0
2 years ago
Could a car drive on a frictionless surface? Explain using the terms action
Julli [10]

Answer:

No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place

7 0
3 years ago
Question 1
frez [133]
B 20 m/s
It should go to 100 that fast nor 40
4 0
3 years ago
A person can jump 1.5m on the earth. How high could the person jump on a planet having the twice the mass of the earth and twice
MrMuchimi
F=mg=Gm1m2/r^2
g=Gm2/r^2
g=2Gm2/(2r)^2=2Gm2/4r^2=Gm2/2r^2
So since there is half times the gravity on this unknown planet that has twice earth's mass and twice it's radius, then the person can jump twice as high. 1.5*2= 3m high

5 0
3 years ago
Read 2 more answers
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