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Kisachek [45]
3 years ago
12

The main difference between a chest and a bounce pass is what?

Physics
2 answers:
wlad13 [49]3 years ago
6 0

Answer:

The main difference is: the chest pass is straight through the air towards your teammate. While the bounce pass is directed toward the ground and then at your teammate.

The secondary main difference is the amount of power from the ball recived from the person reciving

snow_lady [41]3 years ago
4 0

Answer: The main difference between the three is the mode of transmission. The chest pass is straight through the air towards your teammate. While the bounce pass is directed toward the ground and then at your teammate. Finally, the overhead pass is projected high in the air to avoid defenders.

Explanation:

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Light of a given wavelength is used to illuminate the surface of a metal, however, no photoelectrons are emitted. in order to ca
solniwko [45]

We will decrease the wavelength of light in order to cause electrons to be ejected from the surface of this metal.

We have a Light of a given wavelength that is used to illuminate the surface of a metal, however, no photoelectrons are emitted.

We have to find out what can we do in order to cause electrons to be ejected from the surface of this metal.

<h3>What is Photoelectric Effect ?</h3>

The emission of electrons from the surface of the metal when the light of specific frequency (greater than the threshold frequency) falls over it is called photoelectric effect.

Light consists of photons. The energy associated with the photons is used to emit out the electrons from the surface of metal. We know that - Energy can neither be created nor be destroyed and it can only be transferred from one body to another. Hence, the energy of these moving photons is used to emit electrons from the metal surface. The energy associated with the photon is given by -

E = hμ

Where - μ is the frequency of light an h is Planck's constant.

Now, we can see that the energy of the photon is directly proportional to the frequency of light. The minimum frequency required to eject the electron from the metal surface is called Threshold frequency. Thus, we can emit the electron from the metal surface by using the light of frequency greater than threshold frequency.

Hence, we will increase the frequency of light in order to cause electrons to be ejected from the surface of this metal

To solve more questions on Photoelectric Effect, visit the link below -

brainly.com/question/9260704

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8 0
2 years ago
Please help I’m so confused
Ilya [14]

<em>1.wavelength</em>

<em>2.trough</em>

<em>3.amplitude</em>

<em>4.crest</em>

5 0
3 years ago
Can friction ever<br> do positive work?
PtichkaEL [24]

Answer:

say whaaaaaaaat?

Explanation:

hell tho

7 0
3 years ago
If an object that weighs 20 N is lifted from the ground to a
Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

3 0
4 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
poizon [28]

Answer:

391.67Hz

Explanation:

The fundamental frequency formula in string is expressed as;

Fo = V/2L

V is the velocity of the wave = 329m/s

L is the length of the string = 42cm = 0.42m

Substitute

Fo = 329/2(0.42)

Fo = 329/0.84

Fo = 391.67Hertz

Hence the  fundamental frequency of a mandolin string is 391.67Hz

4 0
3 years ago
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