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Solnce55 [7]
3 years ago
10

a person who take 40 paces to cover 20m finds that a square field has a side that is 520 paces long .calculate the length of the

side and the area of the field​
Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
Look at picture for explanation

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A right triangle has a leg length of 21 inches and a hypotenuse length of 29 inches. What is the length of the other leg?​
Shalnov [3]

Answer:

20

Step-by-step explanation:

Pythagorean Theorem: a^2 + b^2 = c^2

21^2 + b^2 = 29^2

441 + b^2 = 841

Subtract 441 on both sides to get b^2 = 400

Take the square root of both sides to get b = 20

4 0
3 years ago
a survey asked two age groups which summer sport they most preferred. the results are shown in the table below. which sport was
pogonyaev

Answer: Hiking was most prefered between ages 20-29

5 0
3 years ago
Read 2 more answers
5x-2y=15<br> 2x+6y=-11<br> solve by substitution or equal values method
g100num [7]

Answer:

Point form -

(2-\frac{5}{2})

Equation form -

x=2, y=-\frac{5}{2}

Step-by-step explanation:

if you have any questions feel free to ask

5 0
3 years ago
1. Determine whether the lines given by the equations 2x + 3y = and y=3/2x+4
son4ous [18]

Answer:

1. Yes, the lines are perpendicular.

2. y=\frac{5}{4}x+6

Step-by-step explanation:

The first equation of Exercise 1 is incomplete. Let's assume that it is:

2x + 3y =n

Where "n" is a number.

First, it is important to remember that the equation of a line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

By definition, the slopes of perpendicular lines are negative reciprocals.

1 . If you solve for "y" from the first equation, you get:

2x + 3y =n\\\\3y=-2x+n\\\\y=-\frac{2}{3}x+\frac{n}{3}

You can identify that the slope is:

m=-\frac{2}{3}

The second equation of the line is:

y=\frac{3}{2}x+4

And its slope is:

m=\frac{3}{2}

Since the slopes are negative reciprocals, the lines are perpendicular.

2. Given the first equation of the line:

y= -\frac{4}{5}x+6

You can identify that:

m=-\frac{4}{5}\\\\b=6

Since the first line and the second one are perpendicular, you know that the slope of the other line is:

m=\frac{5}{4}

According to the information given in the exercise, both lines have the same y-intercept; therefore, the equation of the second line is:

y=\frac{5}{4}x+6

4 0
3 years ago
X+y-4=0. X-y=0. Solution lies in which quadrant
Ann [662]
X+y-4=0, x-y=0 is in the first Quadrant 

5 0
3 years ago
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