7x-3y=23 find x when y=-2

A car's rear windshield wiper rotates 140°. The total length of the wiper mechanism is 24 inches and the length of the wiper bla

Verizon [17]

Answer:

Step-by-step explanation:

This problem is on the mensuration of flat shapes, sectors and arc.

we know that the area of a sector is given as

A=(∅/360)*πr^2

Given that the length of the wiper R=24 in

and the length of the blade r= 16in

To find the area of the wiped surface we only require the length of the blade as the radius

The area of the wiped surface is given as= (140/360)*3.142*16^2

A= 0.3888*3.142*256

A=312.7 in^2

6 0

4 years ago

The square footage of a house is 1200 square feet. What type of data is this?

DIA [1.3K]

The answer for the question shown above is: <span>The square footage of a house that is 1200 square feet is the "</span>Area".

The explanation is shown above:

1- By definition, the area is the measure of a two-dimensional surface.Its units can be written in m^2, ft^2, in^2...However, in the International System of Units is m^2.

2. This is very useful when you want to know the surface of a house. If it is a rectangular house, you can calculate the area as below:

A=LxW

Where L is the length and W is the width

5 0

4 years ago

On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite

Liono4ka [1.6K]

Answer:

b = -a

Step-by-step explanation:

Since a and b are equally distant to zero but in opposite directions, a and b are opposites, or additive inverses.

The sum of additive inverses is zero.

a + b = 0

b = -a

8 0

2 years ago

HELLLLPPPPPPNMEEEEEEEEE!!!!!!

marysya [2.9K]

The answer is
$\frac{ - 7}{4}$

8 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$