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anyanavicka [17]
3 years ago
14

Can radiowaves penetrate clouds​

Physics
1 answer:
lyudmila [28]3 years ago
6 0
Radio waves are reflected, absorbed, scattered, refracted, and diffracted by the atmospheric conditions that they encounter, such as clouds and precipitation. ... For example, only certain wavelengths pass through clouds unimpeded.
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Plz help ASAP I will give brainliest PLZ
Natasha2012 [34]

Answer:

1.8m/s^2

Explanation:

Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.

Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.

Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.

Therefore, 1.8m/s^2 is the correct answer.

Please mark brainliest!

4 0
3 years ago
Read 2 more answers
This is the process of matter changing from the liquid to the solid state.
dlinn [17]

Answer:

freezing

Explanation:

7 0
4 years ago
A current exists whenever electric charges move. If ΔQ is the net charge that passes through a surface during a time period Δt,
jeka57 [31]

Answer:

It represents the change in charge Q from time t = a to t = b

Explanation:

As given in the question the current is defined as the derivative of charge.

                                  I(t) = dQ(t)/dt ..... (i)

But if we take the inegral of the equation (i) for the time interval  from t=a to

t =b we get

                                   Q =∫_a^b▒〖I(t)  〗 dt

which shows the change in charge Q from time t = a to t = b. Form here we can say that, change in charge is defiend as the integral of current for specific interval of time.

5 0
4 years ago
It takes 200 J of work to compress quasi-statically 0.40 mol of an ideal gas to one-fourth its original volume. Calculate the te
mario62 [17]

Answer : The temperature of the gas is, 43.4 K

Explanation :

The expression used for work done will be,

w=-nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 200 J

n = number of moles of gas  = 0.40 mol

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas  = X

V_2 = final volume of gas  = \frac{X}{4}

Now put all the given values in the above formula, we get :

200J=-0.40mol\times 8.314J/moleK\times T\times \ln (\frac{(\frac{X}{4})}{X})

T=43.4K

Thus, the temperature of the gas is, 43.4 K

3 0
4 years ago
How many solutions are there for y=-8+4x y=4x+6
almond37 [142]

Answer:

1

they are not quadratic equations hence the is only one solution to the problem

8 0
3 years ago
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