Question

A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s for the car to complete the turn. At the end of 50 s, the car has a speed of 15 m/s along the side road. Determine the magnitude of average acceleration over the 50 s interval.

Answer 1

Answer:  initial velocity: 20 m/s

                time taken to complete the turn: 50s

               final velocity: 15 m/s

average acceleration= final velocity-initial velocity/time taken - 0s( 0 is taken here as there was no initial time)

           = 15-20/50-0

           = -5/50= -0.1 ms^2