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cestrela7 [59]
3 years ago
14

A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s f

or the car to complete the turn. At the end of 50 s, the car has a speed of 15 m/s along the side road. Determine the magnitude of average acceleration over the 50 s interval.
Physics
1 answer:
Marrrta [24]3 years ago
3 0

Answer:  initial velocity: 20 m/s

                time taken to complete the turn: 50s

               final velocity: 15 m/s

average acceleration= final velocity-initial velocity/time taken - 0s( 0 is taken here as there was no initial time)

           = 15-20/50-0

           = -5/50= -0.1 ms^2

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PLEASE HELP ASAP!!!
I am Lyosha [343]

Answer:

B - Velocity

Explanation:

Velocity definition: “The speed of something in a given direction.”

6 0
2 years ago
In the photoelectric effect, a photon with an energy of 5.3 × 10–19 J strikes an electron in a metal. Of this energy, 3.6 × 10–1
valentina_108 [34]

Answer:

The velocity of the photo electron is 6.11\times 10^5\ m/s.

Explanation:

Given that,

Supplied energy, E_s=5.3\times 10^{-19}\ J

Minimum energy of the electron to escape from the metal, E_e=3.6\times 10^{-19}\ J

We need to find the velocity of the photo electron. The energy supplied by the photon is equal to the sum of minimum escape energy and the kinetic energy of the escaping electron. So,

5.3\times 10^{-19}\ J=3.6\times 10^{-19}\ J+K\\\\K=5.3\times 10^{-19}-3.6\times 10^{-19}\\\\K=1.7\times 10^{-19}\ J

The formula of kinetic energy is given by :

K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1.7\times 10^{-19}}{9.1\times 10^{-31}}} \\\\v=6.11\times 10^5\ m/s

So, the velocity of the photo electron is 6.11\times 10^5\ m/s.

4 0
3 years ago
A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator
cricket20 [7]

Answer:

a)= 98kJ

b)=108kJ

c) = 10kJ

Explanation:

a. The work that is done by gravity on the elevator is:

Work = force * distance  

= mass * gravity * distance

= 1000 * 9.81 * 10  

= 98,000 J

= 98kJ

b)The net force equation in the cable

T - mg = ma

T = m(g+a)

T = 1000(9.8 + 10)

T = 10800N

The work done by the cable is

W = T × d

= 10800N × 10

= 108000

=108kJ

c) PE at 10m = 1000 * 9.81 * 10 = 98,100 J  

Work done by cable = PE +KE  

108,100 J = KE + 98,100 J  

KE = 10,000 J

= 10kJ

=

7 0
3 years ago
Read 2 more answers
What is E of a hydrogen atom in the 3p state?
notsponge [240]

Answer:

E=-1.51 eV.

L=\hbar\sqrt{2}

Explanation:

The nth level energy of a hydrogen atom is defined by the formula,

E_{n}=-\frac{13.6}{n^{2} }

Given in the question, the hydrogen atom is in the 3p state.

Then energy of n=3 state is,

E_{n}=-\frac{13.6}{(3)^{2} }\\E_{n}=-1.51eV

Therefore, energy of the hydrogen atom in the 3p state is -1.51 eV.

Now, the value of L can be calculated as,

L=\hbar\sqrt{l(l+1)}

For 3p state, l=1

L=\hbar\sqrt{1(1+1)}\\L=\hbar\sqrt{2}

Therefore, the value of L of a hydrogen atom in 3p state is L=\hbar\sqrt{2}.

4 0
3 years ago
Can u find the . in this?
nikklg [1K]

Answer:

Yeah it's right there from the one next to the exclamation point

4 0
3 years ago
Read 2 more answers
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