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2 years ago

14

A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s f

or the car to complete the turn. At the end of 50 s, the car has a speed of 15 m/s along the side road. Determine the magnitude of average acceleration over the 50 s interval.

1 answer:

Marrrta [24]2 years ago

3 0

Answer: initial velocity: 20 m/s

time taken to complete the turn: 50s

final velocity: 15 m/s

average acceleration= final velocity-initial velocity/time taken - 0s( 0 is taken here as there was no initial time)

= 15-20/50-0

= -5/50= -0.1 ms^2

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A transparent oil with index of refraction 1.28 spills on the surface of water (index of refraction 1.33), producing a maximum o

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2 years ago

A billiard ball of mass m moving with speed v1=1 m/s collides head-on with a second ball of mass 2m which is at rest. What is th

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From the question w are told that

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Substituting values

$\frac{1}{2} m (1)^2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2$

Multiplying through by $\frac{1}{2}m$

$1 =v_A^2 + 2 v_B ^2 ---(1)$

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$6v_B^2 -4v_B +1 =1$

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Multiplying through by $\frac{1}{v_B}$

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3 years ago

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May be different for you, but i really hope I helped out.

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2 years ago