Answer:
0.95 seconds
Explanation:
t = Time taken
u = Initial velocity = 15 m/s
v = Final velocity
s = Displacement
a = Acceleration = 9.81 m/s² (downward positive, upward negative)
Time taken by the ball to reach the maximum height

Maximum height

Distance between maximum height of the ball and the branch is 11.47-7 = 4.46 m
So, the distance that will be covered on the way down is 4.46 m
Now
u = 0
s = 4.46

Time taken by the ball from the maximum height to the tree branch is 0.95 seconds.
Total time taken from the moment the ball is thrown to reach the tree branch is 1.52+0.95 = 2.47 seconds
The acceleration of the car is 1.067 m/
.
<u>Explanation:</u>
Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.
As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as 
So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

So the acceleration of the car is 1.067 m/
.
After a careful reading of the question, I have concluded that it's a trick question, and that there IS no other one.
Answer:
The unbalanced force that caused the ball to stop was friction
Explanation:
As Newton's second law states, the acceleration of an object is proportional to the net force applied on the object:

therefore, in order to move at constant speed, an object should have a net force of zero (balanced forces) acting on it.
In this case, the ball slows down and eventually comes to a stop: it means that the ball is decelerating, so there are unbalanced forces (net force different from zero) acting on it. The unbalanced force acting on the ball is the friction: friction is a force against the motion of the object, which is due to the contact between the surface of the ball and the surface of the street, and this force is responsible for slowing down the ball.
Sound waves or bounces off the wall and light waves are waves of light