Answer:
D. H (-5,-2) J(-3,-5)K(2,-1)
Step-by-step explanation:
move k down 4 (2,-1)
Like or leave a comment :) have a good one
A) See the attached graph. The purple area appears to be what you want to find.
b) Integrating with respect to x seems much easier. If one were to integrate over y, there would need to be two regions of integration: [1, e^2] and [e^2, e^4].
c)
Answer:
k = 13
smallest zero = -6
Step-by-step explanation:
f(x) is basically the function of x.
x could be any integer. f(x) is the solution of the function of x.
f(x) is defined as x² + 3x - 10
f(x) = x² + 3x - 10
Now, f(x+5) = x² + kx + 30
This statement here says that if the value of x is x+5, then the answer would be x² + kx + 30.
f(x) = x² + 3x - 10
f(x+5) = (x+5)² + 3(x+5) - 10
f(x+5) = x² + 10x + 25 + 3x + 15 - 10
f(x+5) = x² + 13x + 40 - 10
f(x+5) = x² + 13x + 30
x² + 13x + 30 = x² + kx + 30
hence, k = 13
Smallest zero = The smallest x value.
f(x+5) = x² + 13x + 30
Let's take f(x+5) = 0
x² + 13x + 30 = 0
which two numbers products give us 30 and add up to 13?
== 6 and 5
(x+6)(x+5) = 0
x+6 = 0
x = -6
x+5 = 0
x = -5
The two solutions are -6 and -5
The smallest out of these two is -6.
