Which one of the following groups of numbers includes all prime numbers? A. 7, 17, 63, 67 B. 3, 11, 23, 31 C. 1, 3, 11, 23 D. 2,
olganol [36]
The prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.
A.
7 - is a prime number
17 - is a prime number
63 - is not a prime number because 63 = 3 × 21
B.
3 - is a prime number
11 - is a prime number
23 - is a prime number
31 - is a prime number
C.
1 - is not a prime number
D.
2 - is a prime number
3 - is a prime number
5 - is a prime number
15 - is not a prime number because 15 = 3 × 5
Answer:
Step-by-step explanation:
Let r be the radius of the circle, the measure of the arc is equal to:
We can Add/Subtract 7 to the x-value or y-value of the point.
(10, 6)
(10 - 7, 6)
(3, 6)
(10 + 7, 6)
(17, 6)
(10, 6 - 7)
(10, -1)
(10, 6 + 7)
(10, 13)
The only point in the options is (3, 6).
First, you need to set the equation equal to zero:
n^2 + 7n + 10 = 0
Now we factor. We need to find two numbers that add up to 7 and multiply to 10.
2 + 5 = 7
2 * 5 = 10
Now, we just need to write this as a polynomial:
(n + 2) (n + 5)
is our answer.
Hope this helps!
Let's find the least possibilities:
First number: 6
Second number: 8
Third number: 10
6 + 8 + 10 = 24
Now we can see that we are still missing 31 - 24 = 7.
7 can be gained by adding 3 and 4, so:
First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10
9 + 12 + 10 = 31
