Hey Jinx :)
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Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.
y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH
y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY
y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH
y = 200(0.73)^t → (Rate is between 0 and 1) DECAY
y = 4(1/4)^t → (Rate is between 0 and 1) DECAY
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Hope This Helped! Good Luck!
Minimum value of the function is - 2
hope that helps
Answer:
No, modern train cannot travel on old railroad.
Step-by-step explanation:
In rail transport, track gauge is the spacing of the rails on a railway track and is measured between the inner faces of the load-bearing rails.
Most of the modern train are based on broad gauge. The separation in broad gauge is about 5 ft and 6 inches and in the standard gauge the separation between the tracks is 4 ft and 
inches. So for the modern train it is not possible to travel on the tracks whose separation is no more than 4.5 feet.
Answer:
If you are just looking for a simplified answer then the answer is -7x - 3.
Answer: x = 1.1968729357 ; or, round to: 1.2 .
____________________________________________ You would take the "ln" (that is, "natural logarithm") of EACH side of the equation:
ln (e^4x) = ln (120);
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Then continue:
4x ln e = ln 120
4x = ln 120 ; (since "ln e = 1")
then divide EACH side of the equation by "4", to isolate "x" on one side of the equation; and to solve for "x" ;
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4x / 4 = (ln 120) / 4 ;
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x = (ln 120) / 4 ;
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Using a calculator:
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x = (ln 120) / 4 = (4.78749174278) / 4 = 1.1968729357
Answer: x = 1.1968729357 ; or, round to: 1.2 .
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