True
4x^2 -16x +16 = (2x -4)^2
A = 2x
B = 4
Hi there!
First, let's find the slope of the two points using the slope formula (y2 - y1 / x2 - x1).
S = 4 - 2 / 3 - 5
S = 2 / -2
S = -1
Next, we'll plug in the slope and a point into point-slope form (y - y1 = s(x - x1)) in order to find an equation. I will show the work using both points, which will result in two different equations.
(2,5)
y - 5 = -1(x - 2)
y - 5 = -x + 2
y = -x + 7
(4,3)
y - 3 = -1(x - 4)
y - 3 = -x + 4
y = -x + 7
The two equations came out the same! Which is completely okay, and happens sometimes.
Hope this helps!! :)
If there's anything else that you're needing help with, don't be afraid to reach out!
An applicable equation of a vertical parabola in vertex form is:
y-k = a(x-h)^2
Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex. Then,
4-(-1) = a(2-[-1])^2, which becomes 5 = a(9). Therefore, a = 5/9, and the
equation of the parabola is
y+1 = (5/9)(x+1)
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