Answer:
The car was moving approximately at a speed of 37.74 miles per hour.
Step-by-step explanation:
We are given the following in the question:
The stopping distance of a car is given by
where d is the stopping distance in feet and r is speed of the car in miles per hour.
The stopping distance is 75 feet, we have to find the speed of the car,
Putting d = 75 in the equation, we get,
Thus, the car was moving approximately at a speed of 37.74 miles per hour.
Answer:
A= 0.5 and B= 4040
Step-by-step explanation:
If you write out the equation and rearrange a little it gets easier to understand.
( a + b) + (a*b) + (a - b) you can rewrite this as
a + b + a - b + (a*b) this is the same as 2a + ab = 2021
The way I looked at it is to figure out how to get that number 1 at the end.
The number 2020 is easy to get to. How can you get the number 1 using either 2a or ab.
I looked at a = 0.5. 2 times 0.5 would be 1.
So now what would b have to be? We can get the 1 at the end with the 2a part of the equation so now we have to get ab = 2020.
b = 2020/a which using our a = 0.5, you can see that b would have to equal 4040. Test it all out in your equation.
0.5 + 4040 + (0.5 * 4040) + 0.5 - 4040
4040.5 + (2020) - 4039.5 = 2021
So A = 0.5 and B = 4040
Answer:
between 2.8m and 2.9
Step-by-step explanation:
the real answer is 2.83, so between .8 and .9 is correct
Answer: 4
Step-by-step explanation:
18-14=4
