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3 years ago

Consider the following code snippet. Is count < 5 always true, always false, or sometimes true/sometimes false at point 2?

Computers and Technology

1 answer:

AleksAgata [21]3 years ago

8 0

Answer:

c. count 5 is sometimes true/ sometimes false at point 2

Explanation:

The while-loop statement is a conditional looping statement in programming that executes a block of code if a condition is met.

In the program, the value of the count variable is first initialized to zero but the while-loop would continuously increment the count variable by one if the count variable is less than five, which means that the while-loop stops and the code block is not executed at count equal to five.

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In excel, a number can contain the characters__

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Comma and period? You can have numbers like 123,456.78

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3 years ago

Write a public member function which replace that replaces one occurrence of a given item in the ArrayBag with another passed as

ira [324]

Answer:

The method is written in Java

public static boolean abc(int [] ArrayBag,int num, int replace){

Boolean done = false;

for(int i =0; i<ArrayBag.length;i++){

if(ArrayBag[i] == num){

ArrayBag[i] = replace;

done = true;

}

for(int i = 0;i<ArrayBag.length;i++){

System.out.println(ArrayBag[i]+" ");

}

return done;

}

Explanation:

The method is written in java

The arguments of the method are:

1. ArrayBag -> The array declares as integer

2. num -> The array element to check the presence

3. replace - > The replacement variable

This line defines the method as boolean.

public static boolean abc(int [] ArrayBag,int num, int replace){

This line declares a boolean variable as false

Boolean done = false;

The following iterates through the elements of the array

for(int i =0; i<ArrayBag.length;i++){

This checks if the array element exist

if(ArrayBag[i] == num){

If yes, the array element is replaced

ArrayBag[i] = replace;

The boolean variable is updated from false to true

done = true;

}

The following iteration prints the elements of the array

for(int i = 0;i<ArrayBag.length;i++){

System.out.println(ArrayBag[i]+" ");

}

This prints returns the boolean thats indicates if replacement was done or not.

return done;

}

Attached to this solution is the program source file that includes the main method of the program

Download txt

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3 years ago

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Zina [86]

The answer is Flow chart

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3 years ago

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juin [17]

Answer:

The algorithm to find A is even or odd.

input A.
Check the remainder on diving by 2 by A%2.
If remainder is 1 then A is odd Print(Odd).
If remainder is 0 print(Even).

Explanation:

To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.

So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.

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3 years ago

Matts has finished running some security automation scripts on three newly deployed Linux servers. After applying intrusion dete

gizmo_the_mogwai [7]

Answer: CPU

Explanation:

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3 years ago