1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denis23 [38]
3 years ago
6

For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters

and their areas. The class should have three fields: shape, which is of type string, and perimeter and area of type double. The program will have to be able to calculate perimeters and areas for circles, triangles, squares and rectangles, which are the known shapes.
2.1 Constructors
Write these constructors:
1. Default constructor that sets the shape to "unknown" and the perimeter and area to 0
2. Constructor with one parameter, shape, that sets the shape, other fields are 0
2.2 Accessors & Mutators
Write the following member methods:
1. setShape()
Modifies the shape field
2. getShape()
Returns the shape field
3. getPerimeter()
Returns the perimeter field
4. getArea()
Returns the area field
Arithmetic Methods in Interface
Write the following member methods to perform arithmetic:
1. setPerimeter(Scanner scnr)
Depending on the shape, prompts the user for appropriate variables (ie width & height for a square, radius for a circle, etc.) and calculates the perimeter of the appropriate shape. The perimeter field should be updates with the new value. If the shape is unknown, then print to the screen that the user must first define a shape before a perimeter can be calculated and set the perimeter to 0.
2. setArea(Scanner scnr)
Depending on the shape, prompts the user for appropriate variables (ie width & height for a square, radius for a circle, etc.) and calculates the area of the appropriate shape. The area field should be updates with the new value. If the shape is unknown, then print to the screen that the user must first define a shape before an area can be calculated and set the area to 0.
2.3 Additional Methods
Create two additional methods of your choice. Be sure to clearly label both of these methods as your own.
2.4 Using another .java file called ShapesTest.java that tests that all of your methods work correctly
Computers and Technology
1 answer:
maw [93]3 years ago
5 0
<h2>Answer:</h2>

<u />

========= Shape.java  ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

   //required fields

  private String shape;

   private double area;

   private double perimeter;

   //default constructor

  public Shape(){

       this.shape = "unknown";

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //constructor with one parameter

   public Shape(String shape){

       this.setShape(shape);

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //accessors and mutators

  public void setShape(String shape){

       this.shape = shape;

   }

  public String getShape(){

       return this.shape;

   }

   public double getPerimeter(){

       return this.perimeter;

   }

  public double getArea(){

       return this.area;

   }

  public void setPerimeter(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.perimeter = 2 * 3.142 * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.perimeter = 2 * (width + height);

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.perimeter = 4 * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

   }

   public void setArea(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.area = 3.142 * radius * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.area = width * height;

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.area = height * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

   }

   //Own methods

   //1. Method to show the properties of a shape

   public void showProperties(){

       System.out.println();

       System.out.println("The properties of the shape are");

       System.out.println("Shape : " + this.getShape());

       System.out.println("Perimeter : " + this.getPerimeter());

       System.out.println("Area : " + this.getArea());

   

   }

   //2. Method to find and show the difference between the area and perimeter of a shape

   public void getDifference(){

       double diff = this.getArea() - this.getPerimeter();

       System.out.println();

       System.out.println("The difference is " + diff);

   }

}

========= ShapeTest.java  ===========

import java.util.Scanner;

public class ShapeTest {

   public static void main(String [] args){

       Scanner scanner = new Scanner(System.in);

       // create an unknown shape

       Shape shape_unknown = new Shape();

       //get the shape

       System.out.println("The shape is " + shape_unknown.getShape());

       //set the area

       shape_unknown.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_unknown.getArea());

       //set the perimeter

       shape_unknown.setPerimeter(scanner);

       //get the perimeter

       System.out.println("The perimeter is " + shape_unknown.getPerimeter());

       // create another shape - circle

       Shape shape_circle = new Shape("circle");

       //set the area

       shape_circle.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_circle.getArea());

       //set the perimeter

       shape_circle.setPerimeter(scanner);

       //get the area

       System.out.println("The perimeter is " + shape_circle.getArea());

       //get the properties

       shape_circle.showProperties();

       //get the difference between area and perimeter

       shape_circle.getDifference();

   }

}

<h2>Sample output:</h2>

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
57aa40cd91dceaa5454e65fc5d209315.png
You might be interested in
which tag does not display the text in the browser window and makes the sources code mode readable ?​
maxonik [38]

Answer:

HTML comments are not displayed in the browser, but they can help document ... You can add comments to your HTML source by using the following syntax: <! ... you can comment out HTML lines of code, one at a time, to search for errors: ... Use the HTML comment tag to make a comment out of the "This is a comment" text.

Explanation:

Gimme brainliest right now.

3 0
3 years ago
....................................................................................................
r-ruslan [8.4K]

Answer:

......................

..............

......

....

...

..

.

6 0
2 years ago
Why should computers have a file structure?
UkoKoshka [18]
I am guessing "A" because you can store code anywhere and file structure does not prevent viruses.

hope this helped
 <span />
4 0
3 years ago
Read 2 more answers
How to reload ingenuity when a pulsating blue thing is there
Hatshy [7]
Todo is very important
4 0
3 years ago
You have just read about a new security patch that has been made available for your Windows system, so you install the patch as
zhenek [66]

Answer:

A

Explanation:

The best action to take is to download and install the last good update; in that case, it will override the recent unstable update.

An update is not like a single program that can be add or remove from the control panel.

6 0
3 years ago
Other questions:
  • A technician is troubleshooting a computer that will not communicate with any hosts on the local network. While performing a vis
    9·1 answer
  • Does anyone watch The Office?
    14·1 answer
  • We have seen that Internet TCP sockets treat the data being sent as a byte stream but UDP sockets recognize message boundaries.
    13·1 answer
  • While interoperability and unrestricted connectivity is an important trend in networking, the reality is that many diverse syste
    12·1 answer
  • Please help!! Even if you help a little I will be very thankful!
    7·1 answer
  • What differentiates physical design from logical design?
    7·1 answer
  • A strategic information system can be any kind of information system that uses information technology to help an organization __
    11·1 answer
  • Which of these best represents a call to action?
    7·2 answers
  • What programming language does the LMC 'understand'?
    5·1 answer
  • Explain Http and Ftp​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!