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Olenka [21]
3 years ago
6

Help me please I got a timed test :)

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0

Answer:

it's to late I'm sorry I couldn't make it in time

cluponka [151]3 years ago
4 0

Answer:

For everyone who still needs this, the answer is D.

Step-by-step explanation:

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D Cuales son cángulos agudo<br>?​
nasty-shy [4]

Ángulo agudo es aquel que mide menos de 90º

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Bella pays 7 payments of $5 each to a game store.she returns one game receives $20 back.what is the change of the about of money
hichkok12 [17]
15$ would be ya answer ....

6 0
3 years ago
Help! If u get it i will mark brainliest!
konstantin123 [22]

Answer:

Lead-the-market pay strategies. An employer may choose to establish an internal compensation strategy that is in excess of the pay rates in the prevailing marketplace. This compensation strategy may increase the supply of candidates, increase selection rates of qualified applicants, decrease employee turnover, increase morale and productivity, or prevent unionization efforts. However, prior to implementing a lead compensation strategy, an organization should carefully consider what benefits it expects to realize from such a strategy, keeping in mind that this type of structure has the greatest propensity of increasing overall labor costs.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
1) 5.4 +(-9.7)<br> Find the sum
harina [27]

Answer:

-4.3

Step-by-step explanation:

5.4 +(-9.7)

= 5.4-9.7

=-4.3

4 0
3 years ago
Read 2 more answers
Let f(x) be a polynomial such that f(cos θ) = cos(4) θ for all θ. Find f(x). (This is essentially the same as finding cos(4) θ i
Galina-37 [17]

Answer:

f(x) = 8x⁴-8x²+1

Step-by-step explanation:

I will assume that f(cos θ) = cos(4θ). Otherwise, f would not be a polynomial. lets divide cos(4θ) in an expression depending on cos(θ). We use this properties

  • cos(2a) = cos²(a) - sin²(b)
  • sin(2a) = 2sin(a)cos(a)
  • sin²(a) = 1-cos²(a)

cos(4θ) = cos(2 * (2θ) ) = cos²(2θ) - sin²(2θ) = [ cos²(θ)-sin²(θ) ]² - [2cos(θ)sin(θ)]² = [cos²(θ) - ( 1 - cos²(θ) ) ]² - 4cos²(θ)sin²(θ) = [2cos²(θ)-1]² - 4cos²(θ) (1 - cos²(θ) ) = 4 cos⁴(θ) - 4 cos²(θ) + 1 - 4 cos²(θ) + 4 cos⁴(θ) = 8cos⁴(θ) - 8 cos²(θ) + 1

Thus f(cos(θ)) = 8 cos⁴(θ) - 8 cos²(θ) + 1, and, as a result

f(x) = 8x⁴-8x²+1.

5 0
3 years ago
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