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3 years ago

The product of two consecutive even integers is 10 less than 5 times their sum. Find the two integers. Answer in

Mathematics

1 answer:

anyanavicka [17]3 years ago

7 0

Answer:

(0,2) and (8,10)

Step-by-step explanation:

Let the smaller integer be 2n. The larger will be 2x+2.

ATQ. 2n(2n+2)+10=5(4n+2). Solving it, we get 2n=0 or 2n=8. The pairs are (0,2) and (8,10)

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Point A is located at (3,-6) and point A is located at (1-2). What is the scale factor?

Anuta_ua [19.1K]

Answer:

The scale factor is 3.

Step-by-step explanation:

Let the origin O(0,0) is the reference point and the coordinates of the point A are given by (3,-6).

Therefore, the distance OA is given by $\sqrt{(3 - 0)^{2} + (- 6 - 0)^{2}} = 3\sqrt{5}$ units.

Again, the coordinates of point A' are (1,-2).

Therefore, the distance OA' is given by $\sqrt{(1 - 0)^{2} + (- 2 - 0)^{2}} = \sqrt{5}$ units.

Hence, the scale factor is $\frac{OA}{OA'} = \frac{3\sqrt{5} }{\sqrt{5}} = 3$ . (Answer)

4 0

3 years ago

Solve the compound inequality: 3x ≤ 18 AND x + 4 > 2

dedylja [7]

There must be a mistake in your question:
If 3 x ≤ 9, then : x ≤ 3 and :
x + 4 > 2
x > 2 - 4
x > - 2
Answer: D)
Solution set : - 2 < x ≤ 3

4 0

3 years ago

Read 2 more answers

A train is traveling at 60 mph. If the rate of speed increases 4 mph each hour,

Alenkasestr [34]

Answer:

B) 5 hours

Step-by-step explanation:

First, find the amount of mph between 60 and 80:

80 - 60

= 20 mph

Since the speed increases 4 mph per hour, we can find how long it will take to get to 80 mph by dividing 20 by 4:

20/4

= 5

So, the correct answer is B, 5 hours

6 0

2 years ago

Write an equation of each line in point-slope form. containing (2,1) and (3,4)

Leokris [45]

Answer:

y=3x-5

Step-by-step explanation:

This is the only line that will pass through these points.

7 0

3 years ago

Look at the image. (calculus)

mash [69]

<h3>Answer: Choice H) 2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is $\sin^2 x + \cos^2x = 1$

If we were to isolate sine, then,

$\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\$

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, $\cos x = \sqrt{1-\sin^2x}\\\\$

Cosine is also positive in this quadrant.

-------------

So,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2$

Therefore,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2$

is an identity as long as 0 < x < pi/2

5 0

2 years ago

Read 2 more answers