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Gnesinka [82]
3 years ago
12

Garfield (weighing 24 lbs) took a flight to the moon on the space shuttle. As usual, he stuffed himself with lasagna during the

entire flight and napped when he wasn't eating. Much to his delight when he got to the moon he found he weighed only 6 lbs. He immediately proclaimed a quick weight loss diet. Explain the fallacy in his reasoning. Assume gravity on the moon to be about one-sixth that of Earth.
Is it due to the gravitational pull from the moon?
Chemistry
1 answer:
Nata [24]3 years ago
4 0

Answer:

Yes, it is due to the gravitational pull from the moon

Explanation:

The mass of Garfield didn't change during the flight, which is to say, the amount of matter in his body is the same on Earth as on the Moon.

However, <em>weight is a measurement of how strongly mass is pulled towards the ground, due to the gravitational pull.</em>

So even though Garfield's mass is the same, the weight is less due to the lower gravitational pull from the Moon compared to Earth (the weight is one-sixth of the original weight as gravity on the moon is about one-sixth of Earth's). When Garfield returns to Earth, the scale will still read 24 lbs.

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Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at
ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

4Al+3O_2\rightarrow 2Al_2O_3

From the balanced reaction we conclude that

As, 3 mole of O_2 react with 4 mole of Al

So, 0.188 moles of O_2 react with \frac{4}{3}\times 0.188=0.251 moles of Al

From this we conclude that, Al is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 3 mole of O_2 react to give 2 mole of Al_2O_3

So, 0.188 moles of O_2 react to give \frac{2}{3}\times 0.188=0.125 moles of Al_2O_3

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of Al_2O_3 releases amount of heat = 1676 kJ

So, 0.125 mole of Al_2O_3 releases amount of heat = 0.125\times 1676kJ=209.5kJ

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0
3 years ago
Mercury is often used as an expansion medium in a thermometer. The mercury sits in a bulb on the bottom of the thermometer and r
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3 0
3 years ago
Sea, sand, sky, palms – made almost all of
andrezito [222]

Answer:

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Explanation:

3 0
3 years ago
Calculate the amount of time required to raise temperature of 0.50 liter of water from
Burka [1]
<h3>Answer:</h3>

19 seconds

<h3>Explanation:</h3>

Heat energy was supplied and used to heat 0.50 liters of water from 0°C to 10°C.

This means water gained heat energy that was supplied.

Therefore;

Heat supplied = Heat gained by water

We are required to calculate the time taken to raise the temperature of water from 0°C to 10°C.

Step 1: Calculate the heat gained by water

Quantity of heat = Mass × specific heat capacity × change in temperature

Density of water 1 g/ml

Volume of water is 500 mL

Therefore, since Mass = density × volume

The mass of water = 500 g

Change in temperature = 10° C

Specific heat capacity of water = 4.18 J/g/°C

Thus;

Quantity of heat = 500 g × 4.18 J/g/°C × 10

                           = 20,900 Joules

Step 2: Heat supplied by a heater

Heat supplied = Power × time

Power = 1100 J/s

Assuming the time required is x

Heat supplied = 1100x Joules

Step 3: Time required

Remember; heat supplied = heat gained by water

Therefore;

1100x joules = 20,900 Joules

      x = 20,900/1100

        = 19 seconds

Therefore, the time required to raise the temperature of water from 0°C to 10°C is 19 seconds.

6 0
3 years ago
An empty Erlenmeyer flask weighs 241.3 g. When filled with water (d = 1.00 g/cm³), the flask and its contents weigh 489.1 g.
Viefleur [7K]

The answer is- Mass of flask = 608.04 g

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of  mass in terms of density?

  • Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

d = \frac{m}{V}

Thus, mass can be expressed as-

m = d * V

  • Now, mass of empty flask = 241.3 g and the mass of  (flask + Water) = 489.1 g.

Thus, mass of water = 489.1\ g- 241.3\ g = 247.8\ g.

  • Thus, mass of water = 247.8 g and density of water =1.00\ g/cm^3. Its volume is calculated as-

V = \frac{247.8\ g}{1.00\ g/cm^3}=247.8\ cm^3

  • Volume of flask = 247.8 cm^3 .
  • Then when this flask is filled with chloroform (d =1.48 g/cm^3), the mass of chloroform is-

m = d * V = (1.48\ g/cm^3) * (247.8\ cm^3)= 366.74\ g

  • Hence, the mass of flask becomes =241.3\ g + 366.74\ g = 608.04\ g

To learn more about Density and mass, visit:

brainly.com/question/952755

#SPJ4

4 0
1 year ago
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