Answer:
The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.
Explanation:
The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.
An example of an atom that has no charge is one that has a. 2 protons, 2 electrons, and 1 neutron.
To be neutral an atom must have the <em>same number</em> of protons (+) and electrons (-).
Only then will the <em>charges cancel</em> and give a neutral atom.
Answer:
The final temperature is 20.3 °C
Explanation:
Considering that:-
Heat gain by water = Heat lost by brass
Thus,
Where, negative sign signifies heat loss
Or,
For water:
Mass = 300.0 g
Initial temperature = 20.0 °C
Specific heat of water = 4.184 J/g°C
For brass:
Mass = 19.0 g
Initial temperature = 81.7 °C
Specific heat of water = 0.375 J/g°C
So,
<u>Hence, the final temperature is 20.3 °C</u>
Particle exchange energy though elastic collision , hope this helps .
Answer:
6.25×10⁻⁶ g / cm³
Explanation:
Density is the relation between mass and volume as this formula shows.
Density of a compound = Mass of the compound / Volume of compound
In the values, we were given:
0.0124 kg / 1983 mm³ = 6.25×10⁻⁶ kg/mm³
This number means that in a volume of 1 mm³ of compound, the mass of it occupies 6.25×10⁻⁶ kg. Let's make a rule of three:
1 cm³ = 1×10⁻³ mm³
In 1 mm³ we have 6.25×10⁻⁶ kg of compound
So in 1×10⁻³ mm³ we would have (1×10⁻³ mm³ . 6.25×10⁻⁶ kg) / 1 mm³ =
6.25×10⁻⁹ kg
Now let's convert the kg to g.
1 kg = 1000 g
6.25×10⁻⁹ kg . 1000 = 6.25×10⁻⁶ g
Finally density is : 6.25×10⁻⁶ g / cm³
