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Ghella [55]
4 years ago
11

Why is oil unable to dissolve well in water? Water is polar and oil is nonpolar, which means they have no attraction for each ot

her. Oil molecules are too large to fit between the closely spaced water molecules in the liquid state. Water has a greater density than oil, which means that they are not compatible for mixing together. The cohesive properties of water molecules make it difficult for substances like oil to dissolve.
Chemistry
2 answers:
timofeeve [1]4 years ago
5 0

Answer:

Water is polar, oil is non polar, which means they have no attraction for each other

Explanation:

Marat540 [252]4 years ago
3 0
Because water is polar and oil is nonpolar, their molecules are not attracted to each other. The molecules of a polar solvent like water are attracted to other polar molecules, such as those of sugar. This explains why sugar has such a high solubility in water. Ionic compounds, such as sodium chloride, are also highly soluble in water. Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes. This concept is often expressed as “Like dissolves like.” So many substances dissolve in water that it is sometimes called the universal solvent. Water is considered to be essential for life because it can carry just about anything the body needs to take in or needs to get rid of.
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Read the quote: "No tears in the writer, no tears in the reader." Which best explains the meaning of this quote?​
liubo4ka [24]

Answer:

From personal experience

Explanation:

If is not felt by the writer, the reader will not feel it either!

8 0
3 years ago
Which element decreases its oxidation number in this reaction? bicl2 + na2so4 → 2nacl + biso4?
kifflom [539]
The balanced reaction is as follows;
BiCl₂ + Na₂SO₄ --> 2NaCl + BiSO₄
this is a double displacement reaction 
the oxidation number of Bi is +2 in both BiCl₂ and BiSO₄
oxidation number of Cl is -1 in both BiCl₂ and NaCl 
oxidation number of Na is +1 in both Na₂SO₄ and NaCl
oxidation numbers of elements in SO₄²⁻ remains the same in both compounds.Therefore the oxidation state in any of the elements in the reaction doesn't change. Neither of the elements show an increase or decrease in the oxidation numbers .
Answer for this question is no element decreases its oxidation number.

5 0
3 years ago
Read 2 more answers
The chemical equation for the reaction of baking soda (sodium bicarbonate, nahco3) and vinegar (acetic acid, ch3cooh) may be wri
satela [25.4K]
<h3><u>Answer;</u></h3>

Step 1;  NaHCO3(s) + CH3COOH(l)

Step 2 ; CO2(g)

<h3><u>Explanation;</u></h3>
  • The chemical equation for the reaction of baking soda (sodium bicarbonate, NaHCO3) and vinegar (acetic acid, CH3COOH) reaction occurs in two steps.

Step 1;  

  • A double displacement reaction in which acetic acid in the vinegar reacts with sodium bicarbonate to form sodium acetate and carbonic acid:
  • Equation;

NaHCO3(s)+ CH3COOH(l) → CH3COONa(aq) + H2CO3(l)

Step 2;

  • Carbonic acid is unstable and undergoes a decomposition reaction to produce the carbon dioxide gas:

H2CO3(l) → H2O(l) + CO2(g)

3 0
3 years ago
The force that keeps the planets in orbit is________.
erma4kov [3.2K]

Answer:

The force that keeps the planets in orbit is gravity.

4 0
3 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
3 years ago
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