Answer:
t= 4/f+3
Step-by-step explanation:
could you help me with my question i just posted
Answer:
A: 35
Step-by-step explanation:
DG is the combined segments DO and OG. In other words:
We know that DG is 60. DO is (4x-3) and OG is (2x+21). So, substitute:
Solve for x. Combine like terms:
Subtract 18 from both sides:
Divide both sides by 6. Hence, the value of x is:
GO is defined as (2x+21).
So, to find GO, we can now substitute 7 for x and evaluate. Therefore:
Hence, our answer is A.
Step-by-step explanation:
a probability is always
desired cases / total possible cases.
there is the theoretical probability in such cases, where we simply assume that all sides of such a die (or solid) truly have the same probability.
and then we have experimental probability, where we use only the actual data we got in the experiments to calculate the probability of that particular die (with all its actual internal imperfections) to roll certain results.
so, in our experiments how many total cases do we have ?
200.
how many desired cases (a number greater than 10, that means 11 or 12 as result) do we have ?
well, the sum of all appearances of 11s and 12s :
16 + 18 = 34
that means our experimental probability to get a number greater than 10 is
34/200 = 17/100 = 0.17
FYI
while the theoretical probability with an ideal die is
total cases : 12 (1 .. 12)
desired cases : 2 (11, 12)
the probability is
2/12 = 1/6 = 0.166666666...
it is actually a tiny little bit lower than what we observed in the experiments.
Answer:
12 units squared
Step-by-step explanation:
This requires a 3-step solution.
1. The triangle on the left:
To get an area for a triangle, you do: base times height divided by 2.
You get 4/2, which is 2 units squared for the first triangle.
2. The square:
Pretty easy, it is 2 x 2 which is 4.
3. The last triangle:
Same thing as the first triangle, 2 x 6 divided by 2.
You get 12/2 which is 6.
To get the final area: You add them up.
2 + 4 + 6, which is 12.
Find a common denominator, and then find the ones that are equivalent after converting them all to a fraction that has the same denominator.