The effect of doubling the length and width have on the perimeter would be 2x bigger
Answer: 0.0129
Step-by-step explanation:
Given : Sample size : n=32
The average amount of time spent texting over a one-month period is :
Standard deviation :
We assume that the time spent texting over a one-month period is normally distributed.
z-score :
For x= 199
Now by using standard normal table, the probability that the average amount of time spent using text messages is more than 199 minutes will be :-
Hence, the required probability = 0.0129
Answer:
Step-by-step explanation:
lol
Answer:
6
Step-by-step explanation:
hello :
the nth term is : Bn= B1×R^n-1
calculate B3 (when n=3) R= -1/3 B1 = 54
B3 =54×(-1/3)^(3-1)
B3 =54×(1/9)=6
Marta’s unit rate is 10 miles per minute