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igor_vitrenko [27]
3 years ago
5

Find the distance between the pair of points: (6,−3) and (1,0

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\sqrt{34}

»»————- ★ ————-««  

Here’s why:

⸻⸻⸻⸻

\text{\underline{The distance formula is:}}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⸻⸻⸻⸻

\boxed{\text{Calculating the answer....}}\\\\d = \sqrt{(1-6)^2+(0-(-3))^2}\\--------------\\\rightarrow d = \sqrt{(-5)^2+(3)^2}\\\\\rightarrow d = \sqrt{(25+9)}\\\\\rightarrow d =\boxed{ \sqrt{34} }

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.

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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
Simplify the rational expression. State any restrictions on the variable.
natulia [17]

Answer:

t+4, t≠8

Step-by-step explanation:

\dfrac{t^2-4t-32}{t-8}=\dfrac{(t+4)(t-8)}{(t-8)}=t+4

The value of t must not be one that makes the denominator zero, hence must not be 8.

8 0
3 years ago
If the total number of people attending the game was 64,000, how many people were
guapka [62]
Is this the whole question ?
6 0
3 years ago
If you deposit $300 in an account with a 6% interest rate, how much will be in your account after 1 year? $
Fynjy0 [20]

Answer:

336

Step-by-step explanation:

The first year added $18 so just double the lat 2 digits

8 0
2 years ago
A store sells 4 cans of nuts for $7. How much would it cost you to buy 7 cans of nuts?
maksim [4K]

Answer:

12.25

i think thats right

cause you would divided the 7 by four to get you 1.75 then multiply it by 7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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