Answer:
option D
Step-by-step explanation:
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer:
it should be the negative repirocal of -2 so 1/2
N fknvnab;nkfanlvkbdsljnv.jrehv;iavdsirhkebnkljarwnfbnkvbw<em>n;kjnv;kjnrk</em>