Answer:
Step-by-step explanation:
Given that the owner of a motel has 2900 m of fencing and wants to enclose a rectangular plot of land that borders a straight highway.
Fencing is used for 2times length and 1 width if highway side is taken as width
So we have 2l+w = 2900
Or w = 2900-2l
Area of the rectangular region = lw

Use derivative test to find the maximum

So maximum when I derivative =0
i.e when 
Largest area = A(725)
= 
1051250 sqm is area maximum
1/2 base x height
That’s it
Question..
Combine like terms to create an equivalent expression.
½ −⅙q +⅚q - ⅓
Answer:
½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
Step-by-step explanation:
Given
½ −⅙q +⅚q - ⅓
Required
Equivalence
½ −⅙q +⅚q - ⅓
We start by collecting like terms.
⅚q - ⅙q + ½ - ⅓
Factorize
(⅚ - ⅙)q + ½ - ⅓
((5 - 1)/6)q + ½ - ⅓
(4/6)q + ½ - ⅓
Reduce 4/6 to lowest term
⅔q + ½ - ⅓
Evaluate fraction
⅔q + (3 - 2)/6
⅔q + ⅙
Hence, ½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
Answer:
a. 7
Step-by-step explanation:
7x7=49