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Sophie [7]
3 years ago
14

Aubree invested $1,000 in an account paying an interest rate of 6\tfrac{1}{4}6 4 1 ​ % compounded daily. Mia invested $1,000 in

an account paying an interest rate of 6\tfrac{3}{8}6 8 3 ​ % compounded quarterly. After 11 years, how much more money would Mia have in her account than Aubree, to the nearest dollar?
Mathematics
1 answer:
aleksklad [387]3 years ago
7 0

Answer: $17

Step-by-step explanation:

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3. Consider the following information.P(Z) = 0.73P(A) = 0.25P(Z and A) = 0.15Part A: Determine P(Z|A).Part B: Determine P(AZ).I
krok68 [10]

Ok, so:

For Part A, we have: P(Z|A)=P(Z and A)/P(A)

And if we replace, we got:

P(Z|A) = (0.15)/(0.25) and this is equal to 0.6.

For Part B, we have: P(A|Z)=P(Z and A)/P(Z)

P(A|Z) = (0.15)/(0.73) and this is equal to 0.205.

4 0
1 year ago
Trevor had 4 small boxes of raisins to share equally among himself and 2 friends.
ycow [4]
 each person would receive 4/3 of a box of raisins
7 0
3 years ago
Find the volume of 5.4 inches 2 inches 7.1 inches round to the nearest 10th is necessary
WINSTONCH [101]

Answer:

If it is a cube, the answer would be 76.7 .

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Roger brought some sponges. The number of packages he bought was 14 less than the number of sponges per package. Roger bought 51
mihalych1998 [28]

Answer:

the number of sponges per package bought be 32.5

Step-by-step explanation:

Let us assume the number of sponges per package be x

So the number of packages he bought be x - 14

And, the overall he bought 51 sponges

So

the number of packages of sponges did roger buy is

x + x - 14 = 51

2x = 51 + 14

2x = 65

x = 32.5

So the number of sponges per package bought be 32.5

8 0
3 years ago
Simplify the product 3 sqrt 7 (1- sqrt 7)
Dvinal [7]
3\sqrt7(1-\sqrt7)=3\sqrt7\cdot1-3\sqrt7\cdot\sqrt7=3\sqrt7-3\cdot7=3\sqrt7-21

Used:\ \sqrt{a}\cdot\sqrt{a}=a
6 0
3 years ago
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