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2 years ago

I need help dose anyone know

Biology

1 answer:

Westkost [7]2 years ago

7 0

<h2>Option C</h2><h3><em>Anthracite</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em></h3>

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The tundra is cold year-round. it has short cool summers and long, severe winters. The tundra has a permanently frozen sublayer

harkovskaia [24]

I’m pretty sure it is B. Please double check answers tho. It’s been a while since I learned adaptations. Also, if u go to my profile, it says I am 43. I am not a 43 year old middle schooler lol

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3 years ago

Need help with this please

sweet-ann [11.9K]

11- Red
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2 years ago

Why are flowers important to the life cycle of some plants but not others?

Rama09 [41]

Helps with oxygen and stuff

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3 years ago

Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of

Elodia [21]

Answer:

$\boxed {\boxed {\sf 121.905 \ J }}$

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

$q= mc \Delta T$

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

$m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C$

Substitue the values into the formula.

$q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)$

Multiply the first numbers together. The grams will cancel.

$q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)$

Multiply again, this time the degrees Celsius cancels.

$q= 121.905 \ J$

<u>121.905 Joules</u> are required.

5 0

2 years ago

Read 2 more answers

Semisolid media such as MIO are used to determine motility. Another such medium such is SIM (sulfide, indole, motility) medium.

Flauer [41]

Answer:

Explanation:

In this specific scenario, seeing since both of the mediums are differential, the bacteria can grow on either of them, therefore either of them would be a good choice. A differential media allows the researcher to visually distinguish which species have the specific biochemical process. Which in this case both options have the ability to allow bacteria to grow which is what is needed.

8 0

2 years ago