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3 years ago

HELP PLS HELP MEEEEE IM FAILING PYTHAGOREAN THEOREM

Mathematics

1 answer:

Elanso [62]3 years ago

5 0

7^2 + 6^2 = h^2

49 + 36 = h^2

85 = h^2

√85 = h

h = 9.21m

Answered by Gauthmath must click thanks and mark brainliest

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Shay and Nadine solve this problem in two different ways. You have $25$25 in your bank account. You make $7$7 per hour babysitti

brilliants [131]

you need 20 hours babysitting here is how you solve that

you subtract 25 form 165 which is 140 then you divide by 7 which is 20.

your answer is 20.

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3 years ago

Solve the following inequality: 10t + 7 , 200 > 21 , 000

Alla [95]

Answer:

t > 1380

Step-by-step explanation:

Subtract 7200 from both sides

10t + 7200 - 7200 > 21000 - 7200

Simplify

10t > 13800

Divide both sides by 10

10t/10 > 13800/10

Simplify

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3 years ago

Mrs. Lazo bought 9 1/8m. Of curtain cloth. She use 3 5/6m to make a curtain for their bedroom how many meters of cloth were not

sergeinik [125]

Answer:

5 7/24

Step-by-step explanation:

First, you need to make the denominators the same. When you multiply 6 with 4 you get 24, and if you multiply 8 with 3 you get 24. Then you have to multiply the numbers you multiplied with the denominators with the numerator. So, 5 x 4 is 20 and 3 x 1 is 3. Once you put all the numbers together it should look like this: 3 20/24 and 9 3/24. In order to find the answer, you have to subtract the numbers from each other. Which would look like this: 9 3/24 - 3 20/24. But as you can see you can't subtract 3 from 20. So you have to carry the 9. This means you have to subtract 9 from 1, and then you have 27 for the numerator, this then makes it possible to subtract from 20. So then the fractions subtracted from each other is 7 and the whole numbers subtracted from each other is 5 (because the 9 is now 8 since we subtracted one from it). Whole numbers subtracted from each other: 5. Fractions subtracted from each other: 7/24. Add it together you get 5 7/24.

Numerator - the number above the fraction, ex 3 in 3/4

Denominator - the number below the fraction, ex 4 in 3/4

5 0

3 years ago

Please answer the attached question.

Nikitich [7]

Answer : fx + fh - f(x) / h

6 0

3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

3 years ago