A student obtained 2.00 g of pure caffeine following recrystallization from a crude sample, which originally weighed 2.56 g. Wha
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Answer :
(1) The mass of silver nitrate is, 555 g
(2) The solubility of the gas will be, 0.433 g/L
<u>Solution for Part 1 :</u>
From the given data we conclude that
In 100 gram of water, the amount of silver nitrate = 222 g
In 250 gram of water, the amount of silver nitrate =
Therefore, the mass of silver nitrate is, 555 g
<u>Solution for Part 2 :</u>
Formula used : (at constant temperature)
where,
= initial solubility of methane gas = 0.026 g/L
= final solubility of methane gas
= initial pressure of methane gas = 1 atm
= final pressure of methane gas = 0.06 atm
Now put all the given values in the above formula, we get the solubility of methane gas.
Therefore, the solubility of the gas will be, 0.433 g/L
Answer: There are 4.375 moles in 2.5 L of 1.75 M
Explanation:
To calculate the number of moles for given molarity, we use the equation:
Molarity of solution = 1.75 M
Volume of solution = 2.5 L
Putting values in equation , we get: