You are given
200 grams of H2O(s) at an initial temperature of 0°C. you are also given the
final temperature of water after heating at 65°C. You are required to get the
total amount of heat to melt the sample. The specific heat capacity, cp, of
water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for
heat, Q, is
Q = m(cp)(T2-T1)
Q = 200g(4.186
J/g-°C )(65°C - 0°C)
<u>Q =
54,418J</u>
Smog
formed by mixture of smoke and fog
<span>Answer:
Once these values are put into the equation delta Q=mc delta T it will give you the same value for Q (change in energy) if the same fuel is used
50mL will mean it gets heated quicker making the experiment quicker
200mL would take longer to heat for the same change in temperature causing a longer experiment.</span>
