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3 years ago

A separable differential equation is a first-order differential equation that can be algebraically manipulated to look like:

1 answer:

iogann1982 [59]3 years ago

4 0

<span>A separable differential equation is a first-order differential equation that can be algebraically manipulated to look like:

A) f(y)dy = g(x)dx

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Complete the point-slope equations of the line through (3,6) and (5,-8). Use exact numbers.

s2008m [1.1K]

Answer:

y - 6 = - 7(x - 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 6) and (x₂, y₂ ) = (5, - 8)

m = $\frac{-8-6}{5-3}$ = $\frac{-14}{2}$ = - 7

Use either of the 2 points for (a, b)

Using (3, 6), then

y - 6 = - 7(x - 3) ← in point- slope form

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3 years ago

Whats 2+2? geng geng geng geng geng

I am Lyosha [343]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Due tomorrow !!! Ugh

Y_Kistochka [10]

1.) 2
2.) 5
3.)84
4.) 4
5.) 31
6.).5

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3 years ago

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are:

$\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\ \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Answer: Third option

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1 year ago

What is 7.2km/h in m/s?

lukranit [14]

Answer: 2 meters/ seconds

Step-by-step explanation

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3 years ago

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